See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16
Answer:
Step-by-step explanation:
4/(x+23)
Answer:
49.69
Step-by-step explanation:
use Equation for cos15°
cos15°=48y/distance
0.9659=48/Distance
distance=48/0.96592
distance=49.69 yard
5.637 x 10^3 that’s all iv got
Your domain is your x or x value. Therefore your domain should be 19; 20; 21; 22 and your y or y value is your range. Hope this helps