You walked 5/6 mile
1/3(x2)=2/6
1/2(x3)=3/6
5/6 mile
Need to just answer questions but try a maybe
Let the time taken by computer for virus scan be, 'x' days
We are given that Computer A runs a virus scan in every 2.75 days and Computer B runs a virus scan in every 3.5 days.
<h3>Amount of work done by computer A⤵️</h3>
Amount of work done in one day = 
Amount of work done in x days = 
<h3>Amount of work done by Computer B⤵️</h3>
Amount of work done in one day = 
Amount of work done in x days = 
Since, They are doing the same work the amount of work done is 1.
Solve for x ~
➪ <em>Thus, the time taken when both computers run a virus scan at the same time again is, 1.54 days</em>
Answer:
Brandon has <u>18 Dimes and 33 Quarters</u> [Beware: The problem does not state that Brandon owns the coins - he just has them. Check your pockets]
Step-by-step explanation:
Let D and Q stand for the numbers of Dimes(D) and Quarters(Q). <u>I'll use pennies instead of dollars, so avoid the clutter of decimal points</u>.
We are told that:
Q = 2D - 3 [The number of quarters is 3 less than twice the number of dimes.]
and
25Q + 10D = 1005 [total value of $10.05]
Substitute the value of Q in the first equation in the second, so that we have an equation with just one unknown, D.
25(2D-3) + 10D = 1005
50D - 75 + 10D = 1005
60D = 1080
<u>D = 18</u>
<u></u>
Q = 2D - 3
Q = 2(18) - 3
<u>Q = 33</u>
=============================
Check
25Q + 10D = 1005
25(33) + 10(18) = 1005 ?
825 + 180 = 1005 <u>YES</u>
----
Q = 2D - 3 ?
33 = 2(18) - 3 <u>YES</u>
It is a divisor
hope this helps
