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mrs_skeptik [129]
3 years ago
7

Solve algebraically. 6(t-2) + 15t < 5(5 + 3t) With work shown please!!​

Mathematics
2 answers:
sammy [17]3 years ago
8 0

Step-by-step explanation:

6t-12+15t | 25+15t

21t-12 | 25+15t

21t-12 < 25+15t

hence proved..

frez [133]3 years ago
4 0

Answer:

21t - 12 < 25 + 15t

Step-by-step explanation:

<u>6( t - 2 )</u> + 15t <<u> 5 ( 5 + 3t )</u>

  • Distribute .

6t - 12 + 15t < 25 + 15t

  • Combine like terms.

21t - 12 < 25 + 15t.

Hence , <u>Proved</u>.

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A quadrilateral has two angles that measure 222° and 81°. The other two angles are in a ratio of 6:13. What are the measures of
hram777 [196]

\sf\huge\underline{\star Solution:-}

\rightarrow <u>Ratio of two angles are 6:13.</u>

So, let the one angle be \sf{6x} and another be \sf{13x.}

As we know that,

Sum of all interior angles of a quadrilateral = \sf\pink{360°.}

So let's sum up the given angles,

\rightarrow \sf{222°+81°+6x+13x \:=\:  360°}

\rightarrow \sf{303+19x \:=\:  360°}

\rightarrow \sf{19x \:=\:  360-303}

\rightarrow \sf{19x \:=\:  57}

\rightarrow \sf{x \:=\:  \frac{19}{57}}

\rightarrow \sf{x \:=\:  3}

Hence, \sf{x \:=\:  3}

So, First angle \sf{= \:6x\: = \:6×3 \:=} \sf\purple{18°.}

Second angle \sf{= \:13x\: = \:13×3 \:=} \sf\purple{39°.}

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Hope it helps you:)

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