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3 years ago

Sony takes four breathes every 10 seconds during yoga at this rate about how many breaths Sony take on two minutes of yoga

Mathematics

2 answers:

Makovka662 [10]3 years ago

7 0

My best calculations on this problem would have to be 240

34kurt3 years ago

4 0

2 min= 120 seconds
Divide 120 by 10 to see how many 10 seconds are in 120 seconds

120÷10=12

Multiply 12 and 4 to see how many breaths she took

12×4=48

she took 48 breaths in 2 min

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Which is an exponential growth function?

Nataliya [291]

Answer:

$f(x)=120,000(1.055)^{x}$

Step-by-step explanation:

In this problem we have a exponential function of the form

$f(x)=a(b)^{x}$

where

f(x) a home's value

x the number of years

a is the initial value

b is the base

b=(1+r)

r is the rate of grown

we have

a=$120,000

r=5.5%=5.5/100=0.055

b=1+0.055=1.055

substitute

$f(x)=120,000(1.055)^{x}$

6 0

3 years ago

From September 1981 to September 1984 the enrollment at a particular school declined to 11%. If the number of students enrolled

LenaWriter [7]

634, you have to multiply it by 89% of the original number, 712, to deduct 11%

4 0

4 years ago

What is a period in math

jek_recluse [69]

I think is a Decimal

4 0

4 years ago

Read 2 more answers

The 2004 presidential election exit polls from the critical state of Ohio provided the following results. There were 2020 respon

lord [1]

Answer: a) $0.490\leq p\leq0.582$

b) $0.501\leq p$

Step-by-step explanation:

Given : Sample size of respondents in the exit polls : n= 2020

Number of respondents voted for George Bush = 412

Sample proportion: $\hat{p}=\dfrac{412}{768}\approx0.536$

a) Critical value for 99% confidence level : $z_{\alpha/2}=2.576$

Confidence interval for proportion:-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$=0.536\pm (2.576)\sqrt{\dfrac{0.536(1-0.536)}{768}}\\\\=0.536\pm0.046\\\\=(0.490,\ 0.582)$

Hence, the 99% confidence interval for the proportion of college graduates in Ohio that voted for George Bush: $0.490\leq p\leq0.582$

b) Critical value for 95% confidence level : $z_{\alpha/2}=1.96$

Lower confidence bound for the proportion :

$\hat{p}- z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.536-(1.96)\sqrt{\dfrac{0.536(1-0.536)}{768}}\\\\=0.536-0.035=0.501$

Hence, a 95% lower confidence bound for the proportion of college graduates in Ohio that voted for George Bush : $0.501\leq p$

7 0

3 years ago

Read 2 more answers

ASK YOUR TEACHER An article reported that for a sample of 42 kitchens with gas cooking appliances monitored during a one-week pe

xxMikexx [17]

Answer:

$654.16-2.02\frac{165.23}{\sqrt{42}}=602.66$

$654.16+2.02\frac{165.23}{\sqrt{42}}=705.66$

So on this case the 95% confidence interval would be given by (602.66;705.66)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=654.16$ represent the sample mean

$\mu$ population mean (variable of interest)

s=165.23 represent the sample standard deviation

n=42 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=42-1=41$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,41)".And we see that $t_{\alpha/2}=2.02$

Now we have everything in order to replace into formula (1):

$654.16-2.02\frac{165.23}{\sqrt{42}}=602.66$

$654.16+2.02\frac{165.23}{\sqrt{42}}=705.66$

So on this case the 95% confidence interval would be given by (602.66;705.66)

7 0

4 years ago