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natita [175]
3 years ago
5

Sony takes four breathes every 10 seconds during yoga at this rate about how many breaths Sony take on two minutes of yoga

Mathematics
2 answers:
Makovka662 [10]3 years ago
7 0
My best calculations on this problem would have to be 240
34kurt3 years ago
4 0
2 min= 120 seconds
Divide 120 by 10 to see how many 10 seconds are in 120 seconds

120÷10=12

Multiply 12 and 4 to see how many breaths she took

12×4=48

she took 48 breaths in 2 min

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Vertex (-2,2) point (-4,-10)
Jlenok [28]
Vertex form is
y=a(x-h)²+k
vertex is (h,k)
to solve
input the given vertex and then the given point, solve for a


vertex at (-2,2) and a point is (-4,-10)

y=a(x-(-2))²+2
y=a(x+2)²+2
put point (-4,-10)
-10=a(-4+2)²+2
-10=a(-2)²+2
-10=4a+2
-12=4a
-3=a


y=-3(x+2)²+2
7 0
3 years ago
Can you please help me with my math thank you
gayaneshka [121]
2•8.2•5.1=83.64 square feet.
ANSWER: 83.64 Square Feet
7 0
3 years ago
I NEED HELP I WILL GIVE BRAINLIEST!!!
sergiy2304 [10]

Answer:

The probability is 2/5.

Step-by-step explanation:

4/5 is the probability of not getting a 5

1/2 is the probability of flipping heads

4/5x1/2 = 4/10 = 2/5

3 0
3 years ago
Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol
aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

P(A\cap B)=P(A)\times P(B)

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0
3 years ago
Angle ABC has point E on ray BA and point D on ray BC. Points E and D are equidistant from point B. To bisect angle ABC, which o
aivan3 [116]

Answer:

The point in the angle that is equidistant from points E and D

Step-by-step explanation:

I took all three quizzes show me if you have any other questions

3 0
3 years ago
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