Answer:
0.18
Step-by-step explanation:
C is a subpath of A,
first P(A) = 0.6 since the line leading to A says .6
the probability of choosing C is 0.3, but first we have to assume A is chosen. The true probability is 0.3 * 0.6 = 0.18
X is equal to 8. The work for that is on the attached picture.
The events A and B are not independent.
Given that,
P(A|B) = 0.4
P(A) = 0.5
P(B) = 0.8
Two events A and B are said to be independent, if P(A∩B) = P(A) P(B)
We have, P(A|B) = P(A∩B)/P(B)
Therefore, P(A∩B) = P(A|B) P(B) = 0.4 x 0.8 = 0.32
Now P(A) P(B) = 0.5 x 0.8 = 0.4
So P(A∩B) ≠ P(A)P(B)
Therefore, the events A and B are not independent.
Learn more about independent events at brainly.com/question/22881926
#SPJ4
Please find full question attached Answer:
Barbara is not more well off as the typical individual has a higher well being score
Explanation:
please find explanation attached
<em>Hey </em><em>mate!</em><em>!</em>
<em>Answer:</em>
<em>n(</em><em>A)</em><em>=</em><em>1</em><em>2</em>
<em>Solution</em><em>,</em>
<em>A=</em><em>{</em><em>3</em><em>,</em><em>6</em><em>,</em><em>9</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>5</em><em>,</em><em>1</em><em>8</em><em>,</em><em>2</em><em>1</em><em>,</em><em>2</em><em>4</em><em>,</em><em>2</em><em>7</em><em>,</em><em>3</em><em>0</em><em>,</em><em>3</em><em>3</em><em>,</em><em>3</em><em>6</em><em>}</em>
<em>Just </em><em>count </em><em>the </em><em>elements</em><em>,</em>
<em>There </em><em>are </em><em>1</em><em>2</em><em> </em><em>elements </em><em>in </em><em>the </em><em>set.</em>
<em>So </em><em>the </em><em>cardinal </em><em>number </em><em>of </em><em>the </em><em>set </em><em>is </em><em>1</em><em>2</em><em>.</em>
<h2>
<em>Hope </em><em>it </em><em>helps.</em><em>.</em><em>.</em></h2>
