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Leno4ka [110]
3 years ago
14

Solve this equation using elimination: 4x-y=8;6x+y=2

Mathematics
1 answer:
fomenos3 years ago
7 0
Solve simultaneously.

4x - y = 8
6x + y = 2


Multiply top equation by 6, and bottom equation by 4, to eliminate x, so that we can find y.
~
24x - 6y = 48
24x - 4y = 8

Subtract top from bottom to form one equation.
~
-2y = 40
Therefore y is 20.

Put y back in to an equation, such as 4x - y = 8.
~
4x - 20 = 8
4x = 28
x = 7
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Answer:

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Step-by-step explanation:

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Black_prince [1.1K]

The equations which are sums of perfect cubes are as follows;

\rm 8x^6+27x^9+1

\rm x^6+x^3

\rm 27x^9+x^{12}

<h3>Perfect cubes;</h3>

Perfect cubes are the numbers that are the triple product of the same number.

We have to determine

Which are sums of perfect cubes?

1. The given equation is \rm 8x^6+27x^9+1.

The equation can be written as;

\rm 8x^6+27x^9+1\\\\2^3(x^2)^3+3^3(x^3)^3+1^3

All the terms in the expression are can be represented as perfect cubes.

2.  The given equation is \rm 81x^3+16x^6.

The equation can be written as;

\rm 81x^3+16x^6\\\\9^2x^3+4^2(x^2)3

In this, all the terms are not perfect cubes, some of them are squares.

3. The given equation is \rm x^6+x^3.

The equation can be written as;

\rm x^6+x^3\\\\(x^2)^3+x^3

All the terms in the expression are perfect cubes.

4.  The given equation is \rm 27x^9+x^{12}.

The equation can be written as;

\rm 27x^9+x^{12}\\\\3^3(x^3)^3+(x^4)^3

All the terms in the expression are perfect cubes.

5.   The given equation is \rm 9x^3+27x^9.

The equation can be written as;

\rm 9x^3+27x^9\\\\3^2x^3+3^3(x^3)^3

In this, all the terms are not perfect cubes, some of them are squares too.

To know more about perfect cubes click the link given below.

brainly.com/question/4701925

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Answer:

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