F(x)=2x/3x^2-3 what is the domain of the function?

Mathematics

1 answer:

konstantin123 [22]2 years ago

5 0

Answer:

Step-by-step explanation:

$f(x) = \frac{2x}{3x^2 - 3} \\\\ Domain: \\ 3x^2 - 3 ≠ 0 \\ 3x^2 ≠ 3 \\ x^2 ≠ 1 \\ x ≠ \pm 1$

D = {x E R/ x ≠ 1 and x ≠ - 1}

I Hope I've helped you.

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If this triangle is a right triangle, then the Pythagorean theorem would work on it. According to the Pythagorean theorem, $a^2+b^2=c^2$ , so c would always be greater than a or b. In this scenario, the greatest number here is 18, so c = 18. Since a or b don't matter if given both legs, we have the following equation that may or may not be equal: $8^2+11^2=18^2$ . We know 8 squared is 64, and 11 squared is 121, and 18 squared is 324. This means that $64+121=324$ according to the Pythagorean theorem, and since 64 + 121 = 185, and 185 does not equal 324, the Pythagorean theorem does not work and the triangle is not a right triangle.