1. You convert all the numbers into decimals.
a. For 8 1/9 you multiply 8x9 and add the numerator which in this case is one, so the equation would be 8x9=72 then 72+1= 73
b. For 81/10 I used a calculator for accuracy and I just divided 81 by 10 because the fraction line can also be used as a division sign. For this I got 8.1
2. Now I looked at all the numbers I had including the fractions I converted to decimals... 8.115, 8.55, 73, and 8.1
3. Lastly, I put the numbers in order from least to greatest: 8.1, 8.115, 8.55, and 73
4. In order to figure out which one is the smallest and largest, I just added zeros on the end of the numbers so they would all be the same: 8.1-->8.100, 8.115 I kept the same because it already had 3 decimal places, 8.55--> 8.550, and 73--> 73.000
5. Then i could tell which number was the largest by the decimal place numbers.
**Hope this was helpful... It's kind of hard to explain online but hopefully you have a better understanding of how to do it!**
Answer:
y = x^2/ 60 + 15
=>( x - h)^2 = 4a[ (x^2/6 + 15) - k ].
Step-by-step explanation:
Okay, in order to solve this question very well, one thing we must keep at the back of our mind is that the representation for the equation of a parabola is given as ; y = ax^2 + bx + c.
That is to say; y = ax^2 + bx + c is the equation for a parabola. So, we should be expecting our answer to be in this form.
So, from the question above we are given that "the satellite dish will be in the shape of a parabola and will be positioned above the ground such that its focus is 30 ft above the ground"
We will make an assumption that the point on the ground is (0,0) and the focus is (0,30). Thus, the vertex (h,k) = (0,15).
The equation that best describes the equation of the satellite is given as;
(x - h)^2 = 4a( y - k). ------------------------(1).
[Note that if (h,k) = (0,15), then, a = 15].
Hence, (x - 0)^2 = (4 × 15) (y - 15).
x^2 = 60(y - 15).
x^2 = 60y - 900.
60y = x^2 + 900.
y = x^2/ 60 + 15.
Hence, we will have;
(x - h)^2 = 4a[ (x^2/6 + 15) - k ].
Answer:
its y=2
Step-by-step explanation:
Y = 3x + 3
y = x - 1
As you can see, both equations are set to equal y. This means the right sides of each equation are equal, since y is isolated in both equations. So to solve this particular system of equations for x, set the right sides of both equations equal to each other. After you've done that, you can proceed to solve the equation algebraically for the variable, x.
3x + 3 = x - 1
2x + 3 = -1
2x = -4
x = -2
Negative two is the x-value. To find the y-value, substitute -2 for x into either equation and solve algebraically for y.
y = x - 1
y = -2 - 1
y = -3
The final step is to check all work by plugging both x- and y-values back into both equations.
y = 3x + 3
-3 = 3(-2) + 3
-3 = -6 + 3
-3 = -3 -- This is true
y = x - 1
-3 = -2 - 1
-3 = -3 -- This is true.
Answer:
(-2, -3)
