An identification code is to consist of 2 letters followed by 3 digits. how many different codes are possible if repetition is n
2 answers:
Answer:
11232000
Step-by-step explanation:
Given that an identification code is to consist of 2 letters followed by 3 digits.
Also given that repetition is not permitted.
Since order matters here we find that permutation to be used.
Out of 26 letters, 2 letters can be selected without repitition in ways
And 3 codes can be selected from 10 digits in ways
Hence total number of codes =
No of ways = 11232000
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Answer:
Step-by-step explanation:
I'm not sure if you had a typographical error with this statement, "5 to the fourth power, over 25 = 52."
According to the <u>Quotient Rule of Exponents</u><u>:</u>
Method 1:
In order for you apply the Quotient Rule, the base must be the same. Since 5 is a factor of 25, then you could rewrite 25 as 5². Doing so will give you the following exponential expression:
Method 2:
Even if you solve the given problem manually, you'd still get the same answer:
Both methods produced the same result, proving that the correct answer is 25.
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