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Nimfa-mama [501]
3 years ago
10

An identification code is to consist of 2 letters followed by 3 digits. how many different codes are possible if repetition is n

ot permitted
Mathematics
2 answers:
Lena [83]3 years ago
6 0
(26^2)*(10^3)
676*1000
676,000 possibilities
Artemon [7]3 years ago
3 0

Answer:

11232000

Step-by-step explanation:

Given that an identification code is to consist of 2 letters followed by 3 digits.

Also given that repetition is not permitted.

Since order matters here we find that permutation to be used.

Out of 26 letters, 2 letters can be selected without repitition in 26P2 ways

And 3 codes can be selected from 10 digits in 10P3 ways

Hence total number of codes = 10P3(26P2)\\\\=10(9)(8) (26)(25)(24)\\=720(100)(156)\\=11232000

No of ways = 11232000

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Let's find the rates at which Melinda and Marcus are saving money and compare them. 
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So Melinda saved $12 per week.
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5 0
3 years ago
Read 2 more answers
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4 0
3 years ago
Write and solve a system of linear equations: The larger of two numbers is 18 more than 5 times the smaller. If 3 times the larg
marshall27 [118]

Answer:

8 and -2

Step-by-step explanation:

Let the numbers be l and s.

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Solve for s by substituting l into the second equation:

3(5s + 18) + 4s = 16

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2 years ago
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Usimov [2.4K]
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Solve for G<br><br> •1.00<br> •36.03<br> •90<br> •43.34<br> •46.66<br> •7.55
g100num [7]

Answer:42.98

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Hf=√(57)

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G=42.98

6 0
3 years ago
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