An identification code is to consist of 2 letters followed by 3 digits. how many different codes are possible if repetition is n

Question

3 years ago

10

ot permitted

2 answers:

Lena [83] · Answer 1 · 2021-12-30T03:43:08+03:00

Lena [83]3 years ago

6 0

(26^2)*(10^3)
676*1000
676,000 possibilities

Artemon [7] · Answer 2 · 2021-12-30T04:54:12+03:00

Answer:

11232000

Step-by-step explanation:

Given that an identification code is to consist of 2 letters followed by 3 digits.

Also given that repetition is not permitted.

Since order matters here we find that permutation to be used.

Out of 26 letters, 2 letters can be selected without repitition in $26P2$ ways

And 3 codes can be selected from 10 digits in $10P3$ ways

Hence total number of codes = $10P3(26P2)\\\\=10(9)(8) (26)(25)(24)\\=720(100)(156)\\=11232000$

No of ways = 11232000