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Nimfa-mama [501]
3 years ago
10

An identification code is to consist of 2 letters followed by 3 digits. how many different codes are possible if repetition is n

ot permitted
Mathematics
2 answers:
Lena [83]3 years ago
6 0
(26^2)*(10^3)
676*1000
676,000 possibilities
Artemon [7]3 years ago
3 0

Answer:

11232000

Step-by-step explanation:

Given that an identification code is to consist of 2 letters followed by 3 digits.

Also given that repetition is not permitted.

Since order matters here we find that permutation to be used.

Out of 26 letters, 2 letters can be selected without repitition in 26P2 ways

And 3 codes can be selected from 10 digits in 10P3 ways

Hence total number of codes = 10P3(26P2)\\\\=10(9)(8) (26)(25)(24)\\=720(100)(156)\\=11232000

No of ways = 11232000

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a baseball coach collected data to analyze the free throw shooting percentages of players during a game and during practice. The
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Step-by-step explanation:

so fill in 88 where the x is so

y = 0.9 (88) - 1

y = 78.2

4 0
3 years ago
Please help me with both! would really appreciate it
Tamiku [17]
Jus look and the answer above
7 0
3 years ago
Determine whether the given value is a solution of the equation. 36 = k 6 ; k = 6 6 a solution of 36 = k 6 .
Mila [183]

Answer:

Yes: the variable K would equal "6"

Step-by-step explanation:

After you set you equation up, you have to isolate the given variable. To do that you have to do the recipriocal (6k-multiplying) which would be division. You would divide k = 36 ÷ 6 . that isolates the variable ,which you would then solve. k = 6 .

4 0
3 years ago
A fish tank contains 24 L of water. Water is added to increase the volume by 12.5%. What is the new volume of water in the tank?
Ronch [10]

Answer:

27 L

Step-by-step explanation:

To find 12.5% of 24, move the decimal all the way to the left and multiply 24 by 0.125. You get 3, which is how much was added to the original volume.

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6 0
3 years ago
‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️I need help ASAP 30 points and brainliest to correct answer and most helpful. Please elaborate and explain y
Strike441 [17]
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.

What is the theoretical probability that the family has two dogs or two cats?

25% chance

</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa). 

<span>3. Flip both coins 50 times and record your data in a table like the one below.

</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance

<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?

1/8 chance (accidentally messed up there) or 12.5%

</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.

I hope that this helps because it took a while to write out. If it does, please rate as Brainliest

</span>
5 0
3 years ago
Read 2 more answers
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