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3 years ago

Mike spent $7920 on his vacation, which was 11% of his monthly salary. What was his monthly salary

Mathematics

1 answer:

leonid [27]3 years ago

8 0

Answer: $72000

7290 divided by 11 = 720
720 times 100 = 72000

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Evaluate the expression <br> 5.4+ab, if a = 4 and b = 8

dsp73

Answer:

37.4

Step-by-step explanation:

a = 4 and b = 8

change the equation

5.4 + (4) (8)

use P.E.M.D.A.S. and multiply

4*8 = 32

add

5.4 + 32 = 37.4

7 0

3 years ago

What is 2.20 rounded to the nearest tenth?

Musya8 [376]

2.20 rounded to the nearest tenth is 2.2 it is already rounded if it was 2.29 it would be 2.3

7 0

3 years ago

What is the equation of the line that passes through the point (3,-3) and has a slope of 0?

Blizzard [7]

Answer:

given us,

slope= 0

(x1y1)= (3,-3)

here

(y-y1) =m(x-x1)

or, (y+3)=0(x-3)

or (y+3)= x-3

or, x+y= -3-3

x+y= -6

Step-by-step explanation:

x+y= -6

7 0

3 years ago

Nikki has $1100 and spends $35 per week. Mich has $520 and saves $55 per week. In about how many weeks, will Nikki and Micah hav

Rashid [163]

Answer:

6 weeks

Step-by-step explanation:

Given that :

Nikki :

Initial amount = $1100 ;

Amount spent per week = $35

Mich:

Initial amount = $520

Amount saved per week = $55

Number of weeks they'll both have the same amount :

Let number of weeks = w

For Nikki who is spending :

1100 - 35w - - - (1)

For Mich who is saving :

520 + 55w - - - (2)

Equate (1) and (2)

1100 - 35w = 520 + 55w

1100 - 520 = 55w + 35w

580 = 90w

w = 580 / 90

w = 6.444

About 6 weeks

5 0

2 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago