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Darya [45]
3 years ago
12

Jose makes a triangle using three sticks of lengths 20 inches, 21 inches, and 28 inches. Is the

Mathematics
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

no because for right angle triangle the sum of the sq of the two smallest side is equal to the sq of biggest side

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The question on the left is s(t)=-4.9t^2+39.2t+39.2
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which equation has only one solution? A. 6r = 5r + r B. 4m + 5 =25 C. 8v + 11=8v +11 D. 2 - 3p = -3p +5
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B

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PLEASE PLEASE HELP PLEASE THANK YOU I REALLY NEED IT PLEASE !!!! This table shows values represented by an exponential function
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The answer would be A

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Segments KN and LM are transversals. What is true about the measure of angle N?
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Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturd
mestny [16]

Answer:

1) P(X = 8) = 0.1033

P(X = 9) = 0.0688

2) Expected number of 200 restaurants in which exactly 8 customers use the drive-through: 20.66

Expected number of 200 restaurants in which exactly 9 customers use the drive-through: 13.76

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Question 1. Use the Poisson distribution to calculate the probability that exactly 8 cars will use the drive-through between 12:00 midnight and 12:30 AM on a Saturday night at Wendy's. Do the same for exactly 9 cars.

Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturday nights. This means that during 30 minutes, 6 cars expected to arrive. So \mu = 6.

P(X = 8)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 8) = \frac{e^{-6}*(6)^{8}}{(8)!} = 0.1033

P(X = 9)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 9) = \frac{e^{-6}*(6)^{9}}{(9)!} = 0.0688

Question 2. At how many of the 200 restaurants in the survey would you expect exactly 8 customers to use the drive-through? exactly 9 customers?

There is a 10.33 probability that 8 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.1033 = 20.66

There is a 6.88 probability that 9 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.0688 = 13.76

8 0
3 years ago
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