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navik [9.2K]
3 years ago
7

A one-tailed hypothesis test with the t statistic Antisocial personality disorder (ASPD) is characterized by deceitfulness, reck

less disregard for the well-being of others, a diminished capacity for remorse, superficial charm, thrill seeking, and poor behavioral control. ASPD is not normally diagnosed in children or adolescents, but antisocial tendencies can sometimes be recognized in childhood or early adolescence. James Blair and his colleagues have studied the ability of children with antisocial tendencies to recognize facial expressions that depict sadness, happiness, anger, disgust, fear, and surprise. They have found that children with antisocial tendencies have selective impairments, with significantly more difficulty recognizing fearful and sad expressions. Suppose you have a sample of 40 16-year-old children with antisocial tendencies and you are particularly interested in the emotion of disgust. The average 16-year-old has a score on the emotion recognition scale of 11.80. (The higher the score on this scale, the more strongly an emotion has to be displayed to be correctly identified. Therefore, higher scores indicate greater difficulty recognizing the emotion). Assume that scores on the emotion recognition scale are normally distributed.
The null hypothesis is that your sample of children with antisocial tendencies would have no more difficulty recognizing emotion than the general population of 16-year-olds. Stated using symbols:_________. This is a __________ tailed test. Given what you know, you will evaluate this hypothesis using a________ statistic.
Mathematics
1 answer:
OverLord2011 [107]3 years ago
7 0

Step-by-step explanation

The answers in bold is what was required from the question.

the null hypothesis using symbol:-

H₀ : μ = 11.80

the alternative hypothesis using symbol:-

H₁:  μ ≠ 11.80

This is a one tailed test. Given what you know, you will evaluate this hypothesis using a t test statistic.

Alpha level = 0.05

Sample size = n

Degree of freedom = n-1 = 40-1 = 39

To use the t distribution we will have to find the critical value from the t table this value is 1.685

But the question does not have sample mean and sample standard deviation. So I was unable to solve for the standard error

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Find the equaton of the line passing through the points (2,11) and (-8, -19) y= ?x ?​
antoniya [11.8K]

Find the slope:

(-19 - 11) / (-8 - 2) = (-30/-10) = 3

Find the y intercept:

y = mx + b

11 = 3(2) + b

b= 5

So equation is:

y = 3x + 5

5 0
2 years ago
What is the result of subtracting the second equation from the first? <br> -4x-2y=-2<br> x-2y=9
diamong [38]

Answer:

x=2.2

y=-3.4

Step-by-step explanation:

subtract the second from the first

-5x=-11

x=2=2

substituting by x in the first equation

so y=-3.4

6 0
3 years ago
Plz help, I'm taking an Advanced class (Algebra) Will give brainliest ✔✔✔✔✔✔✔✔✔
bija089 [108]

Part A:

The average rate of change refers to a function's slope. Thus, we are going to need to use the slope formula, which is:

m = \dfrac{y_2 - y_1}{x_2 - x_1}

  • (x_1, y_1) and (x_2, y_2) are points on the function

You can see that we are given the x-values for our interval, but we are not given the y-values, which means that we will need to find them ourselves. Remember that the y-values of functions refers to the outputs of the function, so to find the y-values simply use your given x-value in the function and observe the result:

h(0) = 3(5)^0 = 3 \cdot 1 = 3

h(1) = 3(5)^1 = 3 \cdot 5 = 15

h(2) = 3(5)^2 = 3 \cdot 25 = 75

h(3) = 3(5)^3 = 3 \cdot 125 = 375


Now, let's find the slopes for each of the sections of the function:

<u>Section A</u>

m = \dfrac{15 - 3}{1 - 0} = \boxed{12}

<u>Section B</u>

m = \dfrac{375 - 75}{3 - 2} = \boxed{300}


Part B:

In this case, we can find how many times greater the rate of change in Section B is by dividing the slopes together.

\dfrac{m_B}{m_A} = \dfrac{300}{12} = 25


It is 25 times greater. This is because 3(5)^x is an exponential growth function, which grows faster and faster as the x-values get higher and higher. This is unlike a linear function which grows or declines at a constant rate.

7 0
3 years ago
1,200 students registered for an art camp. 945 students showed up. calculate the precent error
Reil [10]

Answer:

255

Step-by-step explanation:

1200-945 is 255

7 0
3 years ago
Read 2 more answers
What is the area, in square centimeters, of a right triangle with side
Yanka [14]

Answer:

210 cm^2

Step-by-step explanation:

Let, a=37 cm, b=35 cm, c= 12 cm

s=(a+b+c)/2 = 42 cm

Δ=\sqrt{s(s-a)(s-b)(s-c)}

Δ= \sqrt{42(5)(7)(30)}

Δ=210 cm^2

5 0
3 years ago
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