Plz help I need help

Mathematics

1 answer:

laiz [17]2 years ago

5 0

Answer:

The answer is most likely -1 31/33

I have a hard time with fractions so I usually just go into my calculator and change it to a decimal. For example with -5 1/3 I would insert 1/3 into my calculator to change it to a decimal and then simply tack on the -5 to it. So in decimal form 1/3 is 0.333... so with the -5 added on its -5.333... Do the same for the other number and then divide. You will get -1.9393... all you have to do is go into your calculator and try out 11/12 or 31/33 to see which equals 0.9393... because those are the only options with a -1. In this case 31/33 equals 0.9393 s -1 31/33 is the answer

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Find the length of the radius of the following circle. (x + 2)2 + y2 = 10 5 √(10) 100

Makovka662 [10]

For this case we have the following equation:

(x + 2) 2 + y2 = 10

We must remember that the standard equation of the circle is given by:

(x - h) 2 + (y - k) 2 = r2

Where r is the radius.

Therefore, in the given equation the radius is:

r ^ 2 = 10

Clearing we have:

R = root (10)

Answer:

The length of the radius of the circle is:

√ (10)

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3 years ago

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How do we find the breadth of square if perimeter and length is given

madreJ [45]

Answer:

A square has 4 sides of equal length, so if you have been given the length, this is also the breadth.

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For example, imagine a square with side length 3 cm. As all four side lengths are equal, the perimeter would be 4 x 3 cm = 12 cm

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2 years ago

B. Determine the values of a and b so that f is continuous. Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$