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Jet001 [13]
3 years ago
15

A music store sold a total of 27 used trumpets and clarinets in one month. Trumpets cost $149 and clarinets cost $99. If total s

ales were $3233, how many clarinets did they sell
Mathematics
1 answer:
Annette [7]3 years ago
4 0

Answer:

The number of clarinets musical store sold was 16. and number of trumpets musical store sold was 11.

Step-by-step explanation:

Let the musical store sells 'x' number of trumpets and 'y' number of clarinets.

According to question,

Total number of  trumpets and clarinets sold is 27 that is

x+y=27 ..............(1)

Also given Trumpets cost $149 and clarinets cost $99.

then the shop sold x trumpets for $149x and sold y clarinets for $99y and total sales were $3233.

thus, 149x+99y=3233  ...........(2)

Solving for equation (1) and (2),

Multiply equation (1) by 149 , we get

(1) ⇒ 149x+149y=4023  ........(3)

Now, subtract equation (3) from equation (2) , we get

149x+149y-(149x+99y)=4023-3233

\Rightarrow 149x+149y-149x-99y=790

\Rightarrow 149y-99y=790

\Rightarrow 50y =790

\Rightarrow y =\frac{790}{50}=15.8

Thus, number of clarinets musical store sold was 15.8 but since clarinets are to be in whole number rounding off to the nearest integer 16.

and put y = 16 in (1) , we get

x+y=27 \Rightarrow x+16=27 \Rightarrow x=27-16=11

Thus, number of trumpets musical store sold was 11.


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Policeman A and Policeman B hand out 70 speeding tickets in a month.
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-2 1/6 + -3 1/3 + -5 1/2
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3 0
2 years ago
In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t
AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

 P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

         r = no. of success which is at least 5 in our case

         p = probability of success which is probability of Roman Catholic of

                 0.90 in our case

So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= \binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}

= 56 * 0.9^{5} * (0.1)^{3} + 28 * 0.9^{6} * (0.1)^{2} + 8 * 0.9^{7} * (0.1)^{1} + 1 * 0.9^{8}

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

3 0
3 years ago
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