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KIM [24]
3 years ago
6

What is the gfm of CO2?

Chemistry
1 answer:
bazaltina [42]3 years ago
4 0

Answer:

44.01 g/mol because its basically the weight

Explanation: 12.0107 + 15.9994*2

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For the following electrochemical reaction: Al3+(aq) + 3e -> Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -> 2F (aq) Calculate
makvit [3.9K]

<u>Answer:</u> The standard electrode potential of the cell is 4.53 V.

<u>Explanation:</u>

We are given:

E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=2.87-(-1.66)=4.53V

Hence, the standard electrode potential of the cell is 4.53 V.

6 0
3 years ago
PLEASE HELP ASAP I NEED IT HELP PEASEEEEEEEEEEE it’s number 4 (this is science)
hoa [83]
Here you go:
Continent Polar - Cold and Dry
Maritime Polar - Cold and Humid
Arctic - Extremely Cold and Dry
Maritime Tropical- Warm and Humid

Hope this helps:)
5 0
3 years ago
How many atoms are in 36.1 g of boron
Katen [24]

Answer:

The answer is 2.011 *10^24

Explanation:

Looking for atoms in boron,

Molar mass of B = 10.81g/mol

There is 36.1g of B,.

Using avogadro constant = 6.023* 10^23

36.1g of B= 6.023 *10^23/10.81 * 36.1g

That is, 6.023*10^23 divided by 10.81 multiplied by 36.1g

From this calculation, we get

36.1g of boron = 2.011 * 10^24atoms.

8 0
3 years ago
Metal M has only one oxidation state and forms a compound with the formula MHCO3. Which formula is correct? A.MNO3 b.MNH4 c.M(NO
never [62]

Answer:

The compound with the correct formula is;

A. MNO₃

Explanation:

The number of oxidation states in the metal, M = One oxidation state

The formula of the compound formed by the metal, M = MHCO₃

We note that the ion HCO₃⁻, known as hydrogen carbonate has an oxidation number of -1

Similarly nitrate, NO₃⁻ has an oxidation number of -1, therefore, the metal M can form similar compound formed with HCO₃⁻ with nitrate, and we have;

The possible compounds formed by the metal 'M' includes MHCO₃ and MNO₃.

5 0
3 years ago
Due in 8 minutes help!!..
svp [43]

Answer:

the answer is b. as you get more heated, you start sweating more.

Explanation:

7 0
3 years ago
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