Answer:
rate= k[A]²[B]²[C]
Explanation:
When concentration of A is increased two times ,keeping other's concentration constant , rate of reaction becomes 4 times .
So rate is proportional to [A]²
When concentration of B is increased two times , keeping other's concentration constant,rate of reaction becomes 4 times.
So rate is proportional to [B]²
When concentration of C is increased two times , keeping other's concentration constant, rate of reaction becomes 2 times.
So rate is proportional to [C]
So rate= k[A]²[B]²[C]
Strong Acid cause it has a very low pH
We know that the element Z = 119 would be placed right below the Fr, in the column of the alcaline metals.
We also know that the trend in the electronegativity is to decrease when you go up-down ia group.
The known electronegativities of the elements of this group are:
Li: 0.98
Na: 0.93
K: 0.82
Rb: 0.82
Cs: 0.79
Fr: 0.70
Then the hypotetical element Z = 119 would probably have an electronegativity slightly below 0.70, for sure in the range 0.60 - 0.70.
The concentration of hydroxide ion is 5 
10^
−
14 M.
<u>Explanation:</u>
Consider the equilibrium of this acid's dissociation,
H
C
l
O
4 ⇌ H
+ + C
l
O 4
-
Moreover, let's assume that H
C
l
O
4 is a strong acid and will fully dissociate.
Hence,
[
H
+
] = 0.20 M
Now, recall,
K
w = [
H
+
]
[
O
H
−
] = 1.0 10
^−
14
Hence,
⇒
[
O
H
−
] = K
w / [
H
+
] = 5 10^
−
14 M.
Answer:
B. Ca(OH)2(s)+CO2(aq)-CaCO3(s)+H2O(aq)
