Answer:
x = 40
y= 20
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin theta = opp / hyp
sin 60 = 20 sqrt(3)/ x
x sin 60 = 20 sqrt(3)
x = 20 sqrt(3)/ sin 60
x = 20 sqrt(3)/ sqrt(3)/2
x = 20 *2
x = 40
tan theta = opp /adj
tan 60 = 20 sqrt(3)/y
y = 20 sqrt(3)/ tan 60
y = 20 sqrt(3) / sqrt(3)
y = 20
R = 2x + 9y [ Given ]
When,
★ Substituting the values in the above equation
=> 13 = 2x + 9 × 3
=> 13 = 2x + 27
=> 13 - 27 = 2x
=> -14 = 2x
=> x = -14/2
=> x = -7
The Pythagorean Theorum formula is a(squared) + b(squared)= c(squared). If you plug in the numbers, the equation is 39(squared) + 80(squared)= c(squared). That simplifies to 1521+6400=c(squared). Adding results in 7921=c(squared). Finally, when you take the square root of both sides, you are left with 89=c (aka the hypotenuse)
Answer:
b^2-4b+3=0
b²-3x-b+3=0
b(b-3)-1(b-3)=0
(b-3)(b-1)=0
either
b=3 or b=1
.
2n^2 + 7 = -4n + 5
2n²+4n+7-5=0
2n²+4n+2=0
2(n²+2n+1)=0
(n+1)²=0/2
:.n=-1
.
x - 3x^2 = 5+ 2x - x^2
0=5+ 2x - x^2-x +3x^2
0=5+x+2x²
2x²+x+5=0
comparing above equation with ax²+bx +c we get
a=2
b=1
c=5
x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1
={-1±√-39}/2
