Let consecutive odd numbers be
x , x+2 , x+4
Smallest number =x
Middle number =x+2
Largest number =x+4
According to condition (x) +(x+2) -27 = 3(x+4)
x+x+2-27= 3(x+4)
2x-25= 3x+12
Subtracting 2x and 12 both sides
2x-25-2x-12=3x+12-2x-12
-37= x this is smallest odd number.
Other two odd numbers are (x+2)= (-37+2)=(-35)
& (x+4)=(-37+4)=(-33)
so three consecutive odd numbers are -37 ,-35 , -33
Answer:
if you meant (b+3)+(2^b-2), the answer is b+1+2^b
Step-by-step explanation:
but if you meant (b+3)+(2b-2), the aanswer is 3b+1
The answer would be 3
g(a)=3^3a-2 and find g(1)
3^3(1)-2
equal: 3
Answer:
Step-by-step explanation:
it's 7/4.
5(x²+x-2x-2)
5(x²-x-2)
5x²-5x-10
you can also simplify to x²-x-2.