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Umnica [9.8K]
3 years ago
7

TriangleABC has three sides with these lengths: AB=9, BC=40, and CA=41, What is the value of cos C?

Mathematics
1 answer:
Otrada [13]3 years ago
3 0

Answer:

9² = 40² + 41² - 2(40)(41) cos(C)

81 = 1600 + 1681 - 3280 cos(C)

81 = 3281 - 3280 cos(C)

-3200 = -3280 cos(C)

cos(C) = 3200 / 3280

cos(C) = 40 / 41

Step-by-step explanation:

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In a completely randomized design involving four treatments, the following information is provided. Treatment 1 Treatment 2 Trea
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Answer:

Option (b) 36.7

Step-by-step explanation:

Data provided in the question:

                       Treatment 1     Treatment 2     Treatment 3      Treatment 4

Sample Size          50                   18                     10                          17

Sample Mean        32                   36                    42                         48

Now,

The overall mean is calculated as

= \frac{\sum_{i = 1}^{4} n_i X_i}{\sum_{i = 1}^{4} {n_i}}

Here, Xi = Sample mean

n = sample sizes

Thus,

Overall mean

= [ (50 × 32) + (18 × 36) + (10 × 42) + (17 × 48) ] ÷ [ 50 + 18 + 10 + 17 ]

= [ 1600 + 648 + 420 + 816 ]  ÷ 95

= 36.67 ≈ 36.7

hence,

Option (b) 36.7

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Step-by-step explanation:

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