Ask question

Ask question

All categories

3 years ago

14

Runa and Jon each start with the same number. Runa rounds to the nearest hundred.jon rounds to the nearest ten.runa's answer is

double jon's answer.Explain how this can be.

1 answer:

Paraphin [41]3 years ago

5 0

Example: 54
Nearest ten: 50
Nearest hundred: 100

You might be interested in

Tickets to Dundee crowns mr.dchs are $3 for students and $5 for adults. The number of adult tickets sold was 195 more than the n

Maurinko [17]

Answer: number of tickets sold to adult = 566

Step-by-step explanation:

Let x = number of tickets sold by DCHS to students.

Let y = number of tickets sold DCHS to adults.

Tickets to Dundee crowns mr.dchs are $3 for students and $5 for adults.

This means cost of total tickets sold to students and adults is $3x and $5y respectively.

If DCHS collected $3943 for the tickets, then we have

3x + 5y = 3943 - - - - - -1

The number of adult tickets sold was 195 more than the number of student tickets. This means

y = x +195.

Put y = x +195 in equation 1

3x + 5(x+195) = 3943

3x + 5x + 975= 3943

8x +975=3943

8x = 3943-975= 2968

x = 2968/8 = 371

y = 371 + 195= 566

4 0

3 years ago

PLEASE HELP ME! CLICK ON THE PICTURE FOR A BETTER VIEW IF U NEED TO!

masya89 [10]

Answer:

In order: -5, 3, 5

Step-by-step explanation:

-5g + 15h - 25

-5 ( g - 3h + 5 )

Hopefully this helps!

Brainliest please?

3 0

2 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

Find last years salary if, after a 4% pay raise, this years salary is $31,200

lilavasa [31]

The answer should be $29,952.... I hope this helps

7 0

2 years ago

Find the distance between each pair of points <br>L(-7,0) ,Y(5,9)

Sedbober [7]

Answer: The distance is 15

Step-by-step explanation:

To find the distance between L and Y find the difference in the x and y coordinates then square them and add them to find their square root.

-7-5= -12

0-9 = -9

12^2 + 9^2 = d^2 where d is the distance

144 + 81 = d^2

225 = d^2

d= $\sqrt{225}$

d= 15

3 0

2 years ago