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torisob [31]
3 years ago
6

Cos (x + π/ 3) + cos (x - π/ 3) = 1 Solve for "x" on the interval [0, 2pi)

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0
\bf cos\left( x+\frac{\pi }{3} \right)+cos\left( x-\frac{\pi }{3} \right)=1\\\\
-----------------------------\\\\\
[cos(x)cos\left( \frac{\pi }{3} \right)\underline{-sin(x)sin\left( \frac{\pi }{3} \right)}] 
+ [cos(x)cos\left( \frac{\pi }{3} \right)\underline{+sin(x)sin\left( \frac{\pi }{3} \right)}]=1
\\\\\\

\bf cos(x)cos\left( \frac{\pi }{3} \right)+cos(x)cos\left( \frac{\pi }{3} \right)=1\implies 2cos(x)cos\left( \frac{\pi }{3} \right)=1
\\\\\\
2cos(x)\cdot \cfrac{1}{2}=1\implies cos(x)=1\implies \measuredangle x=cos^{-1}(1)
\\\\\\
\measuredangle x = 
\begin{cases}
0\\
2\pi 
\end{cases}
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