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3 years ago

Is two over five irrational numbers

Mathematics

1 answer:

9966 [12]3 years ago

4 0

Answer:

No, It is not irrational number.

Step-by-step explanation:

2/5 is a rational number. A rational number is a number of the form q/q where p and q are integers and q is not equal to 0.

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A deli sells sliced meat and cheese. One customer purchases 4 pounds of meat and 5 pounds of cheese for a total of $30.50. A san

Elenna [48]

Answer:x=cost per pound of meat

Y=Cost per pound of cheese

The deli charges 4.50 for a pound of meat

Step-by-step explanation:

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Begin by clearly stating the problem; you can copy this from the problem set file. Show how you solved the problem step by step,

iogann1982 [59]

Answer: 13%

Step-by-step explanation:

We know that the formula to find the simple interest :

$I=Prt$ , where P is the principal amount , r is rate (in decimal )and t is the time period (in years).

Given : Albert borrowed $19,100 for 4 years. The simple interest is $9932.00. Find the rate.

i.e. P = $19,100 and t= 4 years and I = $9932.00

Now, Substitute all the values in the formula , we get

$9932=(19100)r(4)\\\\\Rightarrow\ r=\dfrac{9932}{19100\times4}\\\\\Rightarrow\ r=0.13\ \ \ \text{[On simplifying]}$

In percent, $r=0.13\times100\%=13\%$

Hence, the rate of interest = 13%

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Answer:

Step-by-step explanation:

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#1 is 2 X 10 to the 4th power

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20. (01.03 MC) What is the simplified expression ? (1 point)

ahrayia [7]

Answer:

$\displaystyle 3^2$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Rule [Multiplying]: $\displaystyle b^m \cdot b^n = b^{m + n}$
Exponential Rule [Dividing]: $\displaystyle \frac{b^m}{b^n} = b^{m - n}$

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{3^3 \cdot 3^3}{3^4}$

Step 2: Simplify

[ER] Multiply: $\displaystyle \frac{3^{3+3}}{3^4}$
Add Exponents: $\displaystyle \frac{3^6}{3^4}$
[ER] Divide: $\displaystyle 3^{6 - 4}$
Subtract Exponents: $\displaystyle 3^2$

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3 years ago