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taurus [48]
2 years ago
16

A "golden rectangle” is a rectangle where the ratio of the longer side to the shorter side is the "golden ratio.” These rectangl

es are said to be visually pleasing. An example of a "golden rectangle” has a length equal to x units and a width equal to x – 1 units. Its area is 1 square unit. What is the length of this golden rectangle?
Mathematics
2 answers:
Dahasolnce [82]2 years ago
5 0

Answer:

length of golden rectangle = 1.618

Step-by-step explanation:

It is given that the length (L) of golden rectangle is x

And width (W) of rectangle is x-1

so we have

L = x

W= x-1

Now we have area of rectangle given by

Area = L × W

Area = x(x-1)                             ( we plug L= x and W= x-1)

It is given that area of rectangle is 1 square unit.

So we have

x(x-1)=1\\

x^2 -x=1       ( distribute x and remove parenthesis )

x^2 -x-1=0    ( subtract 1 from both sides )

Now to solve for x we need to use the quadratic formula

For quadratic equation ax^2 +bx+c=0

The quadratic formula is given by x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

Here we have a= 1 , b=-1 c=-1 , so we have

x=\frac{-(-1)\pm\sqrt{(-1)^2 -4(1)(-1) }}{2(1)} \\x=\frac{1\pm\sqrt{1+4} }{2} \\x=\frac{1\pm\sqrt{5} }{2}

x= \frac{1\pm2.236}{2} \\x=\frac{1+2.236}{2}  or  x=\frac{1-2.236}{2}\\

x= 1.618 or x=-0.618

We can not have length negative

hence

length of golden rectangle = 1.618

kari74 [83]2 years ago
4 0
The answer is b. I just did the question and that is the answer
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stepladder [879]

The vector ab has a magnitude of 20 units and is parallel to the

vector 4i + 3j. Hence, The vector AB is 16i + 12j.

<h3>How to find the vector?</h3>

If we have given a vector v of initial point A and terminal point B

v = ai + bj

then the components form as;

AB = xi + yj

Here, xi and yj are the components of the vector.

Given;

The vector ab has a magnitude of 20 units and is parallel to the

vector 4i + 3j.

magnitude

\sqrt{4^2 + 3^2} \\\\\sqrt{16 + 9} \\\\= 5

Unit vector in direction of resultant = (4i + 3j) / 5

Vector of magnitude 20 unit in direction of the resultant

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= 4 x (4i + 3j)

= 16i + 12j

Hence, The vector AB is 16i + 12j.

Learn more about vectors;

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1 year ago
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3 years ago
You are to manufacture a rectangular box with 3 dimensions x, y and z, and volume v=8000. Find the dimensions which minimize the
Inga [223]

Answer:

20 by 20 by 20

Step-by-step explanation:

Let the total surface of the rectangular box be expressed as S = 2xy + 2yz + 2xz

x is the length of the box

y is the width and

z is the height of the box.

S = 2xy + 2yz + 2xz ... 1

Given the volume V = xyz = 8000 ... 2

From equation 2;

z = 8000/xy

Substituting into equation 1;

S = 2xy + 2y(8000/xy)+ 2x(8000/xy)

S = 2xy+16000/x+16000/y

Differentiating the resulting equation with respect to x and y will give;

dS/dx = 2y + (-16000x⁻²)

dS/dx = 2y - 16000/x²

Similarly,

dS/dy = 2x  + (-160000y⁻²)

dS/dy = 2x - 16000/y²

Note that at the turning point, ds/dx = 0 and ds/dy = 0, hence;

2y - 16000/x² = 0 and 2x - 16000/y² = 0

2y = 16000/x² and 2x = 16000/y²

2y = 16000/(8000/y²)²

2y = 16000×y⁴/64,000,000

2y = y⁴/4000

y³ = 8000

y =³√8000

y = 20

Given 2x = 16000/y²

2x = 16000/20²

2x = 16000/400

2x = 40

x = 20

Since Volume of the box is V = xyz

8000 = 20(20)z

8000 = 400z

z = 8000/400

z = 20

Hence, the dimensions which minimize the surface area of this box is 20 by 20 by 20.

3 0
3 years ago
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Viefleur [7K]
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4 0
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Two functions are shown in the table below: Function 1 2 3 4 5 6 f(x) = −x2 + 4x + 12 g(x) = x + 2 Complete the table on your ow
zubka84 [21]

Answer:

x   f(x)   g(x)

1    15    3

2    16   4

3    15    5

4    12    6

5    7     7

6    0     8

f(x) = g(x) when x = 5

Step-by-step explanation:

f(x) = -x² + 4x + 12

f(1) = -(1)² + 4(1) + 12 = 15

f(2) = -(2)² + 4(2) + 12 = 16

f(3) = -(3)² + 4(3) + 12 = 15

f(4) = -(4)² + 4(4) + 12 = 12

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f(6) = -(6)² + 4(6) + 12 = 0

g(x) = x + 2

g(1) = 1 + 2 = 3

g(2) = 2 + 2 = 4

g(3) = 3 + 2 = 5

g(4) = 4 + 2 = 6

g(5) = 5 + 2 = 7

g(6) = 6 + 2 = 8

3 0
3 years ago
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