Answer:
<h3>
Vertex Form</h3>
Step-by-step explanation:
Vertex form of quadratic function with vertex (h, k) is y=a(x-h)²+k,
So y= (x - 2)² - 9 is vertex form with vertex (2, -9)
Hey
2x+x+x+2y*3y*y
=4x+6y^3
=2(2x+3y^3)
Idk but pointsss???????????????
Answer:
w = π/2
Step-by-step explanation:
I used trig identities (double angle) to solve this problem.
Step 1: Rearrange problem
2cos²(w) - cos(w) - 1 = 0
2cos²(w) - 1 - cos(w) = 0
Step 2: Trig Identity
cos2w - cos(w) = 0
Step 3: Combine like terms
cosw = 0
Step 4: Solve
w = cos^-1(0)
w = π/2
I may have done it wrong so don't rely too much on me
