TRUE...................................................................
The plane you want is parallel to another plane, <em>x</em> - <em>y</em> + <em>z</em> = -5, so they share a normal vector. In this case, it's ⟨1, -1, 1⟩.
The plane must also pass through the point (0, 4, 4) since it contains <em>r</em><em>(t)</em>. Then the equation of the plane is
⟨<em>x</em>, <em>y</em> - 4, <em>z</em> - 4⟩ • ⟨1, -1, 1⟩ = 0
<em>x</em> - (<em>y</em> - 4) + (<em>z</em> - 4) = 0
<em>x</em> - <em>y</em> + <em>z</em> = 0
Given:
Right triangle XYZ has right angle Z.

To find:
The value of
.
Solution:
We know that,



For a triangle, all trigonometric ratios are positive. So,

It is given that
. After substituting this value in the above equation, we get




On further simplification, we get


Therefore, the required value is
.
Answer:
2.14 cm^3
Step-by-step explanation:
V = 4/3 pi r^3
V = 4/3 pi 0.512
V = 2.14
Answer:
Step-by-step explanation:
