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Naya [18.7K]
3 years ago
13

You have used 2.4×102 L of distilled water for a dialysis patient. How many gallons of water is that?

Chemistry
1 answer:
Alinara [238K]3 years ago
3 0

Answer:

63.36gallons

Explanation:

Given:

Volume of water used for dialysis = 2.4 x 10²L

Solution:

We are to convert from liters to gallons.

The conversion factor is shown below:

                1L = 0.264gallons

To convert to litre:

       since 1L = 0.264gallons

             2.4 x 10²L = (2.4 x 10² x 0.264)gallons; 63.36gallons

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You have been given an orange liquid and told to describe its properties.
chubhunter [2.5K]

Answer:

The correct answer would be - observing with the help of five senses.

Explanation:

To find and describe the physical properties of the given substance or the solution or liquid students can observe using their five senses. By looking at the liquid one can find its state and color, by smelling students can find the odor of the sample, by touching it one can observe and describe the texture.

Fluidity can also be measure by the touch if the solution is viscous or free-floating. By using a thermometer and using a graduated cylinder one can find the temperature at room temperature and the weight of substance respectively.

5 0
3 years ago
how many moles of potassium hydroxide are needed to completely react with 1.73 miles of aluminum sulfate according to the follow
Masteriza [31]
<h3><u>Answer; </u></h3>

=10.38  moles KOH  

<h3><u>Explanation</u>;</h3>

The balanced equation.  

6KOH + Al2(SO4)3 --> 3K2SO4 + 2Al(OH)3  

From the equation;

1 mole of aluminum sulfate requires 6 moles of potassium hydroxide.  

Moles of Aluminium sulfate;  1.73 moles

Moles of KOH;

1 mol Al2(SO4)3 : 6 mol KOH = 1.73  mol Al2(SO4)3 : x mol KOH  

Thus; x =  (6 × 1.73)

              <u> =10.38 moles KOH </u>

4 0
3 years ago
Read 2 more answers
A student dissolves 3.9g of aniline (C6H5NH2) in 200.mL of a solvent with a density of 1.05 g/mL . The student notices that the
tino4ka555 [31]

Answer:

2.1 × 10⁻¹ M

2.0 × 10⁻¹ m

Explanation:

Molarity

The molar mass of aniline (solute) is 93.13 g/mol. The moles corresponding to 3.9 g are:

3.9 g × (1 mol/93.13 g) = 0.042 mol

The volume of the solution is 200 mL (0.200 L). The molarity of aniline is:

M = 0.042 mol/0.200 L = 0.21 M = 2.1 × 10⁻¹ M

Molality

The moles of solute are 0.042 mol.

The density of the solvent is 1.05 g/mL. The mass corresponding to 200 mL is:

200 mL × 1.05 g/mL = 210 g = 0.210 kg

The molality of aniline is:

m = 0.042 mol/0.210 kg = 0.20 m = 2.0 × 10⁻¹ m

5 0
3 years ago
A balloon has a volume of 6.2 liters at 23.2 C. The balloon is then heated to a temperature of 144.0 C. What is the volume of th
Marina CMI [18]

Answer:

8.7 L

Explanation:

T2(V1/T1) = V2

417.15 K(6.2 L/296.45 K) = 8.7 L

Remember to almost always change celcius to kelvin. Also, this is part of Charle's Law (temp and volume are proportional, so if temp increaces so must the volume or vice versa). Lastly, Charle's Law has the formula of V1/T1 = V2/T2. I just rearranged it to go along with your problem. Hence, the T2(V1/T1) = V2

4 0
3 years ago
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andrezito [222]
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5 0
3 years ago
Read 2 more answers
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