Molar mass of Neon ( Ne ) = 20.1797 g/mol
m = n * mm
m = 125 * 20.1797
m = 2522.4625 g
hope this helps!
<h3>
Answer:</h3>
- Balanced Equation; 2Fe + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂
- Why balance?: To obey the law of conservation of mass
- Subscripts can not be changed, since they show the actual number of atoms of each element in a compound.
<h3>
Explanation:</h3>
- The balanced equation for the reaction between the iron metal and sulfuric acid to produces iron (III) sulfate and hydrogen gas is given by;
2Fe + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂
- Balancing chemical equations ensures that they obey the law of conservation of mass which requires the mass of reactants and the mass of products to be equal.
- Balancing is done by putting coefficients on reactants and products while not affecting the subscripts as subscripts show the actual number of atoms of an element in a compound.
Lowery-Bronsted theory is applied here. Acc. to this theory Base accepts protons and Acids donate proton.
Part 1:
Aniline is less basic than ethylamine because the lone pair on nitrogen (which accepts proton) is not localized. It resonates throughout the conjugated system of phenyl ring. Hence due to unavailability of electrons for accepting proton it is less basic compare to ethylamine. In ethyl amine the lone pair of electron is localized and available to abstract proton.
Part 2:
In this case the alkyl groups attached to -NH₂ (in ethylamine) and -O⁻ (in ethoxide are same (i.e. CH₃-CH₂-). Ethoxide is more basic than ethylamine because ethoxide is a conjugate base of ethanol (pKa value of ethanol = 15.9 very weak acid) and the conjugate base of weak acid is always a strong base. Secondly, the oxygen atom more Electronegative than Nitrogen atom can attract more electron cloud from alkyl group as compared to Nitrogen in ethylamine. Hence, oxygen in ethoxide attains greater electron cloud than the nitrogen in ethylamine. Therefore, it is more basic than ethylamine.
A) chemical - gas produced
took the test sorry for being a day late.
The element "X" is "O" (oxygen).
<h3>Calculation:</h3>
Given,
Chemical formula = Na₂CX₃
Formula mass = 106 amu
Molar mass of Na = 23 amu
Molar mass of C = 12 amu
To find,
Element X =?
We will equate the equation as follows,
2(23) + 12 + 3(y) = 106
46 + 12 + 3y =106
58 + 3y = 106
3y = 106 - 58
3y = 48
y = 48/3
y = 16
We know that Oxygen has molecular mass of 16. Therefore the element "X" is "O".
Learn more about molar mass here:
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