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Ad libitum [116K]
3 years ago
11

Before raw data can be used as scientific evidence, it must be analyzed and summarized. One way of summarizing data is to find t

he mean, or average, of a set of data points. What method is used for calculating the mean?
Chemistry
1 answer:
Sindrei [870]3 years ago
7 0
To calculate the mean, you add up all of the data values, and then divide that sum by the *number* of values.

For instance, if you wanted to find the mean score at a home run derby, and you’re given the following numbers for home runs scored by each player:

5, 4, 6, 5, 3, 1

You could calculate the mean by adding all of the score up

5 + 4 + 6 + 5 + 3 + 1 = 24

And dividing by the number of hitters (in this case, 6)

24 / 6 = 4

So the *mean score* of the home run derby would be 4.

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A student dissolves of urea in of a solvent with a density of . The student notices that the volume of the solvent does not chan
Dimas [21]

The question incomplete , the complete question is:

A student dissolves of 18.0 g urea in 200.0 mL of a solvent with a density of 0.95 g/mL . The student notices that the volume of the solvent does not change when the urea dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to significant digits.

Answer:

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

Explanation:

Moles of urea = \frac{18.0 g}{60 g/mol}=0.3 mol

Volume of the solution = 200.0 mL = 0.2 L (1 mL = 0.001 L)

Molarity(M)=\frac{\text{Moles of compound}}{\text{Volume of solution in L}}

Molarity of the urea solution ;

M=\frac{0.3 mol}{0.200 L}=1.50 M

Mass of solvent = m

Volume of solvent = V = 200.0 mL

Density of the urea = d = 0.95 g/mL

m=d\times V=0.95 g/mL\times 200.0 mL=190 g

m = 190 g = 190 \times 0.001 kg = 0.19 kg

(1 g = 0.001 kg)

Molality of the urea solution ;

Molality(m)=\frac{\text{Moles of compound}}{\text{Mass of solvent in kg}}

m=\frac{0.3 mol}{0.19 kg}=1.58 m

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

7 0
2 years ago
Given bh3, o3, co2, and nh3, which of these compound is an exception to the octet rules?.
Ghella [55]

Answer:

a. BH₃

Explanation:

According to the octet rules, atoms reach stability when are surrounded by eight electrons in their valence shell when they combine to form a chemical compound.

From the options, the only compound in which the central atom does not meet the octet rules is BH₃. The central atom is boron (B), which has 3 electrons in its valence shell. When B is combined with hydrogen (H), 3 electrons from the 3 atoms of H are added. The total amount of electrons is 6, fewer than 8 electrons needed to meet the rule.

hope this helps

5 0
2 years ago
If nitrogen and hydrogen combine in a combustion reaction, what would the product of the reaction be?
kow [346]

Co2

Explanation:

CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)

4 0
3 years ago
Read 2 more answers
How are salinity, temperature and circulation related?
frosja888 [35]

Answer:

Salinity, along with temperature, determines the density of seawater, and hence its vertical flow patterns in thermohaline circulation. 2. Salinity records the physical processes affecting a water mass when it was last at the surface. Hope this helps!

Explanation:

4 0
3 years ago
What is the ∆G for the following reaction between O3 and O2? 3O2(g) 2O3(g) Given: O3: ∆H = 285.4 kJ ∆S = -137.14 J/K)
Natali [406]
We’ll be using the equation:
dG = dH - TdS (replace ‘d’ with triangle)

I’m going to assume 0 degrees Celsius.
At 0 C (273 K):

dG = dH - TdS
dG = (285,400 J) - (273 K)(-137.14 J/K)
dG = 285,400 J + 37,439.2 J
dG = 322,839.2 J or 322.84 kJ

The dG of this reaction is +322.84 kJ. This reaction is not considered spontaneous.

This answer, in this instance, would be D. If the temperature used in the question is not 0 degrees C, replace the temperature that I used for calculation with the Kelvin temperature given in the problem (K = C + 273), and simplify to find the answer.
6 0
3 years ago
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