We want to see which offer is the best one to buy 40 batteries, by using algebra we will see that the best offer is offer-B
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How to find the best offer?</h3>
Here we just need to see which would be the cost of 40 batteries which each offer.
For offer-A, a pack of 4 costs £2.52 and we have 1/3 off.
For 40 batteries the cost will be 10 times the above quantity, we get:
10* £2.52 = £25.20
But there is a 1/3 off, so the cost would be 2/3 of the above quantity:
£25.20*(2/3) = £16.80
For offer-B we know that a pack of 5 costs £2.75, so you need to buy 8 of these. And for each 3 you get one free, so you need to buy 6 (and get 2 free ones). The cost of 6 of these is:
6*£2.75 = $16.50
From this, we can conclude that offer-B is the best one.
If you want to learn more about algebra, you can read:
brainly.com/question/8120556
P(> or =70) =0.65
P(Collins inside) =0.80
P(not 70) = 1-P(70) =>0.35
P(Collins inside) = 0.1
Then P(70 AND Collin inside) .65 x .8 =0.52
P( not 70 AND Collin Outside = 0.35 x 0.1=0.035
TOTAL Possibility [(70 AND Inside) OR (not 70 AND Outside):
=0.52 + 0.034 =0.555
Answer:
Enter the equations.
Multiply each equation by a number to get the lowest common multiple for one of the variables.
Add or subtract the two equations to eliminate that variable .
Substitute that variable into one of the equations and solve for the other variable.
