Answer and explanation:
There are six main trigonometric ratios, namely: sine, cosine, tangent, cosecant, secant, cotangent.
Those ratios relate two sides of a right triangle and one angle.
Assume the following features and measures of a right triangle ABC
- right angle: B, measure β
- hypotenuse (opposite to angle B): length b
- angle C: measure γ
- vertical leg (opposite to angle C): length c
- horizontal leg (opposite to angle A): length a
- angle A: measure α
Then, the trigonometric ratios are:
- sine (α) = opposite leg / hypotenuse = a / b
- cosine (α) = adjacent leg / hypotenuse = c / b
- tangent (α) = opposite leg / adjacent leg = a / c
- cosecant (α) = 1 / sine (α) = b / a
- secant (α) = 1 / cosine (α) = b / c
- cotangent (α) = 1 / tangent (α) = c / b
Then, if you know one angle (other than the right one) of a right triangle, and any of the sides you can determine any of the other sides.
For instance, assume an angle to be 30º, and the lenght of the hypotenuse to measure 5 units.
- sine (30º) = opposite leg / 5 ⇒ opposite leg = 5 × sine (30º) = 2.5
- cosine (30º) = adjacent leg / 5 ⇒ adjacent leg = 5 × cosine (30º) = 4.3
Thus, you have solved for the two unknown sides of the triangle. The three sides are 2.5, 4.3, and 5.
Just Try 84 Bro..............
You can use substitution and solve y-x=2 for y which is y= x+ 2 and plug it into the y of the other equasion and you get x=5 y=7
