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qwelly [4]
3 years ago
6

A new app charges an annual fee plus an additional fee per new game downloaded. The table shows the linear relationship between

the number of new games downloaded and the total cost including the annual fee. Which statement is true?
A.
The additional fee per game is $10.

B.
The additional fee per game is $1.99.

C.
The annual fee is $1.99.

D.
The annual fee is $19.99.

Mathematics
1 answer:
gogolik [260]3 years ago
6 0

The correct answer is below:

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Your class earned $110.00 Saturday afternoon by washing cars to raise money for a class trip. This is 14 of the money needed for
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Answer

D. 440

Step-by-step explanation:

you had me confused so I had to go in my mathmetics book it was 1/4 not 14 thats what had me confused

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"Express as a mixed numeral: 39/8" is a problem found in a fifth-grade arithmetic textbook. This problem is BEST solved through:
Scilla [17]

Answer:

  c.  an algorithm

Step-by-step explanation:

Most math problems are best solved using an algorithm. Certainly, converting numbers from one form to another is easily done that way.

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The integer part is the whole-number quotient of the division. The fractional part is the remainder divided by the denominator:

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Each big square below represents one whole.<br><br> what percent is represented by the shaded area?
morpeh [17]

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100/27

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6 0
3 years ago
[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
3 years ago
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