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vaieri [72.5K]
3 years ago
11

What is the difference in the rate of change between the two containers?

Mathematics
1 answer:
Hunter-Best [27]3 years ago
4 0
Changed the graph to a table so you could see what I did to find slope and the difference. Attached work.

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Find two fractions whose sum is 2/3 but neither denominator is 3
frosja888 [35]
The answer to this question is 1/2 + 1/1
6 0
3 years ago
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Kite GHIJ has sides GH, HI, IJ and JG. What are the diagonals of this figure? Select all that apply.
juin [17]

Answer:

  GI or HJ

Step-by-step explanation:

Diagonals connect non-adjacent vertices.

That is, the diagonal with G as an endpoint will not connect to vertices H or J, but will connect to vertex I. Likewise the diagonal with H as one end will have J as the other end. A quadrilateral has only two (2) diagonals. Of course, each can be named two ways:

 GI or IG

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6 0
3 years ago
A farmer has a collapsable grain bag which can expand both vertically and horizontally as he needs it to. He wants to find a fun
bija089 [108]

Answer:

3x^{3}+15x^{2}+x+5

Step-by-step explanation:

We are told that the area of the bag can be represented by the function f(x)=3x^{2} +1 and as the bag is raised up its height can be represented by the function g(x)=x +5.

Since we know that we can find volume of cuboid by multiplying base area to its height. We are given area and height of bag as functions. Now we will find volume of the bag by multiplying these functions.  

\text{Volume of collapsible bag}=f(x)*g(x)  

\text{Volume of collapsible bag}=(3x^{2}+1)*(x +5)

After using distributive property we will get,

\text{Volume of collapsible bag}=3x^{2}(x+5)+1(x+5)

\text{Volume of collapsible bag}=3x^{3}+15x^{2}+x+5

Therefore, the collapsible bag can hold 3x^{3}+15x^{2}+x+5 grain.

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3 years ago
Write first 10 pirme numbers and find median
likoan [24]

Answer:

2 3 5 7 11 13 17 19 23 27

Step-by-step explanation:

12 I think

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3 years ago
How i can find 7 times 754 using two different methods
g100num [7]
You can add 754 7 times, or just multiply regularly.
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3 years ago
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