A piece of paper is randomly selected from a stack that contains 15 small, 44 large, and zu extra large pieces.

Anna is a teacher at an elementary school. She purchased 73 tickets to take the first-grade children and some parents on a field

Svetllana [295]

She bought 54 child tickets and 19 adult tickets.

Step-by-step explanation:

No. of tickets purchased = 73

Cost of tickets = $771

Cost of one child ticket = $9

Cost of one adult ticket = $15

Let,

Child ticket = x

Adult ticket = y

According to given statement;

x+y=73 Eqn 1

9x+15y=771 Eqn 2

Multiplying Eqn 1 by 9;

$9(x+y=73)\\9x+9y=657\ \ \ Eqn\ 3\\$

Subtracting Eqn 3 from Eqn 2;

$(9x+15y)-(9x+9y)=771-657\\9x+15y-9x-9y=114\\6y=114\\$

Dividing both sides by 6;

$\frac{6y}{6}=\frac{114}{6}\\y=19$

Putting y=19 in Eqn 1

$x+19=73\\x=73-19\\x=54\\$

She bought 54 child tickets and 19 adult tickets.

Keywords: linear equations, subtraction

Learn more about linear equations at:

#LearnwithBrainly

4 0

2 years ago

Suppose that F is an inverse square force field below, where c is a constant.

Andre45 [30]

Answer:

Forces in our Universe

Step-by-step explanation:

a)

First of all we have,

$F(r) = \frac{cr}{|r|^{3} }$

and,

$r = xi+yj+zk$

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

$f(r) = - c /|r|$

That is,

$\nabla f = F$

For this case F is a conservative field and the line integral is independent of the path. Thus, defining $P_{1} = (x_{1}, y_{1}, z_{1})$ and $P_{2} = (x_{2}, y_{2}, z_{2})$ . So the amount of work on the movement of the object from P1 to P2 is,

$W=\int\limits_c {F} \, dr$

$W= f(P_{1}-P_{2})$

$W= \frac{c}{(x_{2}^2+ y_{2}^2+ z_{2}^2)^{1/2} } -\frac{c}{(x_{1}^2+ y_{1}^2+ z_{1}^2)^{1/2}}$

$W= c(\frac{1}{d1}-\frac{1}{d2} )$

2) The gravitational force field is given by,

$F(r) =-\frac{mMGr}{ |r|^3}$

The maximum distance from the earth to the sun is $1.52*10 ^ 8$ km and the minimum distance is $1.47*10 ^ 8$ km. The mass values of the bodies are given by m = $5.97*10 ^ {24}$ kg, M = $1.99 *19 ^ {30}$ kg and the constant G is $6.67 * 10 ^{ -11 }$ $\frac{Nm ^ 2}{kg^2}$

In this way we raise the problem like this,

$c= -mMG$

$W= -mMG (\frac{1}{1.52*10 ^ 8} -\frac{1}{1.47*10 ^ 8} )$

$W= -(5.95*10^{24})(1.99*10^{30})(6.67*10^{-11})(-2.2377*10^{-10})$

$W \approx 1.77*10^{35}}J$

5 0

2 years ago

2x - 8 X-3 4. What is the value of x? (a) 3 (c) 9 (b) 15 (d) 30 5 3

azamat

I believe it’s 9 but unsure sorry

5 0

2 years ago

What is 5 devided by 1/8th

RSB [31]

The answer would be 40

5 divided by 1/8

5/1 divided by 1/8
5/1 divided by 8/1
then you would multiply
5 times 8
=40/1 or 40

7 0

3 years ago

Read 2 more answers

How do you solve log x = 4?

antoniya [11.8K]

In order to solve this, We will want to change it into an exponential form. Assuming that since we do not have a number beside log, It will be log base 10.

10^4=x

We can now solve for x.

This means that x= 10,000

4 0

3 years ago

Read 2 more answers