The exponent for that would be 13^3.
If the answer is incorrect, then i am sorry.
By changing the number into a decimal, and then moving the decimal twice to the right.
<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
(-2d^2+s)(5d^2-6s)
= (-2d^2*5d^2 + s*5d^2 -2d^2*-6s + s*-6s
= -10d^4 + 5sd^2 + 12sd^2 - 6s^2
=-10d^2 + 17sd^2 - 6s^2
This is the final result