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Dominik [7]
3 years ago
12

Factor the following expression 14x + 49​

Mathematics
2 answers:
Vlad [161]3 years ago
5 0
Answer 7(2x+7)

The GCF is 7 therefore you factor out the GCF (write the GCF first then divide each term by 7

7(14x/7 + 49/7)

So that would give you: 7(2x+7)
xxTIMURxx [149]3 years ago
4 0

Answer:

7(2x +7)

Step-by-step explanation:

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PLEASE HELP!!<br>What is the sum of the measures of the exterior angles of this triangle?
RideAnS [48]

282

Step-by-step explanation:

C=180-112=68

A=180-68-51=61

sum of exterior angles=112+119+51=282

4 0
3 years ago
I need help. once again. bahahaha
katrin [286]

Answer:

letters d. and e.

5 0
3 years ago
Solve x to the second power = 144
vfiekz [6]

x ^ 2 = 144

x = 12, x = -12

Check:

12 * 12 = 144

-12 * -12 = 144

6 0
3 years ago
Read 2 more answers
The directrix of a parabola is x = 4. Its focus is (2,6) .
Sati [7]

Answer:

Step-by-step explanation:

If you plot the directrix and the focus, you can see that the focus is to the left of the directrix.  Since a parabola ALWAYS wraps itself around the focus, our parabola opens sideways, to the left to be specific.  The formula for the parabola that opens to the left is

-(y-k)^2=4p(x-h)

We will solve this for x at the end.  The negative is out front because it opens to the left.  If it opened to the right, it would be positive.

The vertex of a parabola is exactly halfway between the focus and the directrix, so our vertex coordinates h and k are (3, 6). P is defined as the distance between the vertex and the directrix, or the vertex and the focus.  Since the vertex is directly between both the directrix and the focus, each distance is the same.  P = 1.  Filling in what we have now:

-(y-6)^2=4(1)(x-3) which simplifies to

-(y-6)^2=4(x-3)

Now we will solve it for x.

-(y-6)^2=4x-12 and

-(y-6)^2+12=4x so

-\frac{1}{4}(y-6)^2+12=x

4 0
4 years ago
3-2i/1+4i include each step necessary in simplifying
Likurg_2 [28]

Answer:

\frac{3-2i}{1+4i}=\frac{11}{17}-\frac{10}{17}i

Step-by-step explanation:

\frac{3-2i}{1+4i} <-- Given

\frac{3-2i}{1+4i}*\frac{1-4i}{1-4i} <-- Multiply by the conjugate of the denominator as a factor of 1

\frac{(3-2i)(1-4i)}{(1+4i)(1-4i)}

\frac{(3)(1)+3(-4i)-2i(1)-2i(4i)}{(1)(1)+1(-4i)+4i(1)+4i(-4i)} <-- Use the Distributive Property and FOIL

\frac{3-12i-2i-8i^2}{1-4i+4i-16i^2}

\frac{3-10i-8i^2}{1-16i^2}

\frac{3-10i-8(-1)}{1-16(-1)} <-- Rewrite i^2 as -1

\frac{3-10i+8}{1+16}

\frac{11-10i}{17}

\frac{11}{17}-\frac{10}{17}i <-- Rewrite in a\pm bi form

8 0
3 years ago
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