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3 years ago

Which factors are needed to determine the amount of heat absorbed by an aluminum cube after it is warmed?

Chemistry

1 answer:

xxMikexx [17]3 years ago

3 0

Answer:

final temperature of the cube

initial temperature of the cube

mass of the cube

specific heat of aluminum

Explanation:

Let me know if you need any other help:)

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Answer:

Q=mcΔT

Explanation:

The formula for expressing the amount of heat transferred between energy stores is given by the equation. The specific heat capacity of water is 4180 J/kgoC (Joules per kilogram per degree), this means it takes 4180 J of heat energy to raise the temperature of 1 kg of water by 1oC.

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2 years ago

What conducts better, metal or nometal? why?

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There are some data that suggest that zinc lozenges can significantly shorten the duration of a cold. If the solubility of zinc

zhuklara [117]

Answer:

$K_{sp}$ of $Zn(CH_{3}COO)_{2}$ is 0.0513

Explanation:

Solubility equilibrium of $Zn(CH_{3}COO)_{2}$ :

$Zn(CH_{3}COO)_{2}\rightleftharpoons Zn^{2+}+2CH_{3}COO^{-}$

Solubility product of $Zn(CH_{3}COO)_{2}$ ( $K_{sp}$ ) is written as- $K_{sp}=[Zn^{2+}][CH_{3}COO^{-}]^{2}$

Where $[Zn^{2+}]$ and $[CH_{3}COO^{-}]$ represents equilibrium concentration (in molarity) of $Zn^{2+}$ and $CH_{3}COO^{-}$ respectively.

Molar mass of $Zn(CH_{3}COO)_{2}$ = 183.48 g/mol

So, solubility of $Zn(CH_{3}COO)_{2}$ = $\frac{43.0}{183.48}M$ = 0.234M

1 mol of $Zn(CH_{3}COO)_{2}$ gives 1 mol of $Zn^{2+}$ and 2 moles of $CH_{3}COO^{-}$ upon dissociation.

so, $[Zn^{2+}]$ = 0.234 M and $[CH_{3}COO^{-}]$ = $(2\times 0.234)M=0.468M$

so, $K_{sp}=(0.234)\times (0.468)^{2}=0.0513$

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Answer:

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