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Valentin [98]
3 years ago
11

In a crystal lattice of an ionic compound,

Chemistry
1 answer:
Lena [83]3 years ago
6 0

Answer:

i would try B

Explanation:

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Calculate the mass of bromine in 50.0 g of potassium bromide
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Answer:

6 Percent Composition. 1. Molar Mass of KBr K = 1(39.10) = 39.10 Br =1(79.90) =79.90 MM = 119.0 79.90 g        119.0 g = 0.6714 3. 0.6714 x 50.0g = 33.6 g Br 2.

4 0
3 years ago
Determine the formula weight of caffeine, C₈H₁₀N₄O₂. Provide an answer to two decimal places.
arlik [135]

Let's find

\\ \tt\hookrightarrow C_8H_10N_4O_2

  • We need accurate mass

\\ \tt\hookrightarrow 8(12.011)+10(1.007)+4(14.006)+2(16.0)

\\ \tt\hookrightarrow 96.088+10.07+56.024+32.0

\\ \tt\hookrightarrow 196.182g/mol

\\ \tt\hookrightarrow 196.18g/mol\:or 196.18u

5 0
2 years ago
Read 2 more answers
During the nuclear fission process, the transformation between a parent and daughter isotope involves a a release of neutrons an
denis-greek [22]

Answer:

The energy harnessed in nuclei is released in nuclear reactions. Fission is the splitting of a heavy nucleus into lighter nuclei and fusion is the combining of nuclei to form a bigger and heavier nucleus. The consequence of fission or fusion is the absorption or release of energy.

Introduction

7 0
2 years ago
How many moles of FeCI3 are present in 345.0 g FeCI3
Sphinxa [80]

Answer:

\boxed {\boxed {\sf About \ 2.127 \ moles \ of \ FeCl_3}}

Explanation:

To convert from moles to grams, the molar mass must be used.

1. Find Molar Mass

The compound is iron (III) chloride: FeCl₃

First, find the molar masses of the individual elements in the compound: iron (Fe) and chlorine (Cl).

  • Fe:  55.84 g/mol
  • Cl:  35.45 g/mol

There are 3 atoms of chlorine, denoted by the subscript after Cl. Multiply the molar mass of chlorine by 3 and add iron's molar mass.

  • FeCl₃: 3(35.45 g/mol)+(55.84 g/mol)=162.19 g/mol

This number tells us the grams of FeCl₃ in 1 mole.

2. Calculate Moles

Use the number as a ratio.

\frac{162.19 \ g \ FeCl_3}{1 \ mol \ FeCl_3}

Multiply by the given number of grams, 345.0.

345.0 \ g \ FeCl_3 *\frac{162.19 \ g \ FeCl_3}{1 \ mol \ FeCl_3}

Flip the fraction so the grams of FeCl₃ will cancel.

345.0 \ g \ FeCl_3 *\frac{1 \ mol \ FeCl_3}{162.19 \ g \ FeCl_3}

345.0 *\frac{1 \ mol \ FeCl_3}{162.19 }

\frac{345.0 \ mol \ FeCl_3}{162.19 }

Divide.

2.12713484 \ mol \ FeCl_3

3. Round

The original measurement of grams, 345.0, has 4 significant figures. We must round our answer to 4 sig figs.

For the answer we calculated, that is the thousandth place.

The 1 in the ten thousandth place tells us to leave the 7 in the thousandth place.

\approx 2.127 \ mol \ FeCl_3

There are about <u>2.127 mole</u>s of iron (III) chloride in 345.0 grams.

6 0
3 years ago
Someone please help will mark as brainliest
Tju [1.3M]

Answer: The answer is D.

Explanation: The warm water will cause the sugar to dissolve quicker.

5 0
3 years ago
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