Answer:
—96.03°C
Explanation:
We'll begin by writing out the information provided by the question. This includes:
Number of mole (n) = 0.645 mole
Volume (V) = 2.00 L
Pressure (P) = 4.68 atm
Temperature (T) =?
Recall: that the gas constant = 0.082atm.L/Kmol
With the ideal gas equation PV = nRT, the temperature of the gas can be obtained as follow:
PV = nRT
4.68 x 2 = 0.645 x 0.082 x T
Divide both side 0.645 x 0.082
T = (4.68 x 2) /(0.645 x 0.082)
T = 176.97 K
Now, We can also express the temperature obtained in celsius as shown below:
Temperature (celsius) = temperature (Kelvin) - 273
Temperature (celsius) = 176.97 - 273
Temperature (celsius) = —96.03°C
The temperature of the Neon gas is
—96.03°C
Possible answer could be: P/T = k
Other factors that affect how much light<span> is absorbed, reflected and </span>scattered concerns<span> the </span>light<span> itself and how it arrived at the surface of the </span>object<span>, such as the wavelength (color) of the </span>light<span>, and. the angle at which it reaches the surface.</span>
Answer:
correct substrate to bind the active site of the enzyme.
Explanation:
For an enzyme to catalyze a chemical reaction it is very essential for the correct substrate to bind the active site of the enzyme.
The Active site consists of two parts
1.Binding site
2. Catalytic site
The binding site consists of amino acid residues that bind to the correct substrate while the catalytic site has the amino acids that lead to the catalysis.
The active site's shape is such that only the right substratum easily binds to it and thus the catalytic reaction occurs.
We are going to use this formula:
Q = M*C*ΔT
when Q is the heat required
M is the mass of CCl4 = 10.35 g
C is the specific heat capacity of CCl4 = 0.874J/g.c
and ΔT the change in temperature = 56.4 - 32.1 °C =24.3 °C
∴ Q = 10.35g * 0.874 * 24.3 °C
= 219.8 J
