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Step2247 [10]
3 years ago
9

Round 919,827 to each place value in the table

Mathematics
2 answers:
Alchen [17]3 years ago
8 0

Nearest 1000: 920,000

Nearest 100: 919,800

Nearest 10: 919,830

Alexeev081 [22]3 years ago
7 0

Answer:

nearest 1000- 10,000

nearest 100- 800

nearest 10- 30

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Feliz [49]

Answer:

135

Step-by-step explanation:

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3 years ago
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determine if you can use the HL congruence theorem to prove the triangles congruent. if not, tell what else you need to know
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I need an actual picture to solve this
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Barry is 8 years older than his sister. In 3 years, he will be twice as old as she will be then. How old is each now?
Colt1911 [192]

Answer:

Step-by-step explanation:

Present age of Barry = b

Present age of sister = s

Barry is 8 years older than his sister means if we subtract 8 from present age of Barry both will be of equal age

s=b-8 ............(1)

In 3 years means we have to add 3 in their present age

s+3=b+3

then

he will be twice as old as

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2s+6=b+3

2s=b+3-6

2s=b-3...............(2)

Put the value of s from (1) to (2), we have

2(b-8)=b-3

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b=13

Put the value of b in (1)

s=13-8

s=5

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Present age of sister = s = 5

7 0
3 years ago
Y = x +4<br> 3x + y = 16
Vesna [10]

Answer:

x= 3 while fo y = 7 that's the answer

5 0
3 years ago
What radius of a circle is required to inscribe a regular hexagon with an area of 210.44 cm2 and an apothem of 7.794 cm
alekssr [168]
We know that

[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
</span>210.44=6*[area of one equilateral triangle]
[area of one equilateral triangle]=210.44/6-----> 35.07 cm²

[area of one equilateral triangle]=b*h/2
h=7.794 cm
b=2*area/h------> b=2*35.07/7.794------>b= 9 cm

the length side of a regular hexagon is 9 cm
<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm

<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
</span>
the answer is
the radius is 9 cm
8 0
3 years ago
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