2 years ago

If y is a differentiable function of x, then the slope of the tangent to the curve xy-2y 4y^2=6 at the point where y=1 is

1 answer:

7 0

x(1^2)-2(1)+4(1^3)=6
x - 2 + 4 = 6
x + 2 = 6
x = 4

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