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maw [93]
3 years ago
7

What is the derivative of arctan (y/x) with respect to y??

Mathematics
1 answer:
ycow [4]3 years ago
8 0
<span>arctan(y/x) = d/dx
                  =1/x∗1/(1+(y/x<span>)^2</span>)</span>
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Someone help me pls
koban [17]

Answer:

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6 0
3 years ago
Which conversion factors can be used to find the number of hours in a week? Select all that apply.
Archy [21]

Answer:

3rd and 4th options are correct that is 24 hours per day and 7 days per week.

Step-by-step explanation:

We need to find the conversion factors that can be used to find number of hours in a week.

We know that,

Number of hours in a day = 24

and

Number of days in a week = 7

So, Number of hours in 7 days = 24 × 7 = 168.

Therefore, 3rd and 4th options are correct that is 24 hours per day and 7 days per week.

6 0
3 years ago
Are the lines 2y-10x=4 and y-2=5x parallel ??
aleksandrvk [35]
Well,

If the slope of the lines are the same, then the lines are parralel.

We need to manipulate 2y - 10x = 4 into y = mx + b form.

Add 10x to both sides
2y = 10x + 4

Divide both sides by 2
y = 5x + 2

Do the same thing with the other equation.

Add 2 to both sides
y = 5x + 2

y = 5x + 2

It appears that, not only are they parallel, but they lie on exactly the same line! If this was a System of Simultaneous Linear Equations, then there would be an infinite number of solutions!<span />
5 0
4 years ago
Read 2 more answers
Construct a quadrilateral ABCD, AB = 4cm BC = 3cm,<br> AD= 2.5cm, AC= 4.5cm, BD= 4cm.
hammer [34]

Answer:

steps below

Step-by-step explanation:

1. use ruler to draw a segment of 4 units AB

2. center the compasses needle at A and draw arc with radius of 5 and intersect with another arc centered at B with radius of 3 at point C

3. center the compasses needle at B and draw arc with radius of 4.5 and intersect with another arc centered at A with radius of 2.5 at point D

4. connect BC, CD and AD to form quadrilateral ABCD

6 0
3 years ago
Write the quadratic equation whose roots are 6 and -4 , and whose leading coefficient is 5. (Use the letter x to represent the v
BaLLatris [955]

The quadratic equation for this would be f(x) = 5x^2 - 10x - 120.

In order to find that, we need to start by taking our x intercept values and setting them equal to zero.

x = 6 ----> subtract 6 from both sides

x - 6 = 0

x = -4 ----> add 4 to both sides

x + 4 = 0

Now that we have both of these zero terms, we can multiply them to get a standard form.

f(x) = (x - 6)(x + 4)

And while this will give us the zeros we need, it will no give us the lead coefficient. So we must multiply by the desired lead coefficient.

f(x) = 5(x - 6)(x + 4)

f(x) = 5(x^2 - 6x + 4x - 24)

f(x) = 5(x^2 - 2x - 24)

f(x) = 5x^2 - 10x - 120

7 0
4 years ago
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