Answer:
(A)![[x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}]](https://tex.z-dn.net/?f=%5Bx-%282%2Bi%29%5D%5Bx-%282-i%29%5D%5Bx-%5Csqrt%7B2%7D%5D%5Bx%2B%5Csqrt%7B2%7D%5D)
Step-by-step explanation:
A polynomial has a leading coefficient of 1 and the following factors with multiplicity 1:

We apply the following to find the factored form of the polynomial.
- If a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial.
- If the polynomial has an irrational root
, where a and b are rational and b is not a perfect square, then it has also a conjugate root
.

Therefore, the factored form of the polynomial is:
![[x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}]](https://tex.z-dn.net/?f=%5Bx-%282%2Bi%29%5D%5Bx-%282-i%29%5D%5Bx-%5Csqrt%7B2%7D%5D%5Bx%2B%5Csqrt%7B2%7D%5D)
Answer:
The answer is(A) -23
Step-by-step explanation:
that's it
Look the answer up on quizlet
For this case what you should see is the behavior of each function to find the correct answer.
We have functions of the type:
f (t) = a * (b) ^ t
Thus,
For I, we have:
f (t) = 30 * (1.05) ^ t
For V we have:
f (t) = 30 * (0.95) ^ t
For VI we have:
f (t) = 30 * (0.85) ^ t
Answer:
option c.
<h3>
Answer: the fraction -8/117</h3>
----------------
First, convert to an improper fraction
3 & 1/4 = 3 + (1/4)
3 & 1/4 = (12/4) + (1/4)
3 & 1/4 = 13/4
The mixed number 3&1/4 turns into the improper fraction 13/4
---------------
-2/9 divided by (3&1/4) = -2/9 divided by 13/4
To divide two fractions, you flip the second one and then you multiply
"-2/9 divided by 13/4" turns into "-2/9 times 4/13" after this happens
Then you multiply straight across. The numerators stick together. The denominators stick together.
numerators: -2*4 = -8
denominators: 9*13 = 117
We end up with the fraction -8/117
This cannot be reduced as there are no common factors (other than 1) between 8 and 117.