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Nana76 [90]
3 years ago
5

Can someone find slope ?

Mathematics
2 answers:
Lana71 [14]3 years ago
3 0
Negative. It’s the only one that makes since. ( probably)
irakobra [83]3 years ago
3 0
3/-4 possibly........
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-10÷_100(20+501) that is my home work
KIM [24]

Answer:

-52.1

Step-by-step explanation:

-10/100 = -0.1

-0.1 x 20 = -2

-0.1 x 501 = -50.1

                  +    -2

                   ____

                -52.1

5 0
3 years ago
What is the next number of the pattern. 2 7 26 101 400
aliina [53]
the\ sequence\ can\ be\ determined\ recursively:\\\\ \left \{ {\big{a_1=2\ \ \ \ \ \ \ \ \ \ \ \ \ \ } \atop\big {a_{n+1}=4\cdot a_n-n}} \right. \\\\\\a_6=4\cdot a_5-5=4\cdot400-4=1600-5=1595\\\\Ans.\ the\ nxt\ term\ is\ 1595.
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3 years ago
Read 2 more answers
Point I is on line segment
Katyanochek1 [597]

Answer:

Step-by-step explanation:

the answer is 14

6 0
3 years ago
Two angles are supplementary. One angle can be represented by 2x, while the other by 3x-10. What is the value of 2x? Based on th
liubo4ka [24]
Supplementary angles = 180
2x +3x-10 = 180
5x -10 =180
5x -10 +10 =180+10
5x =190
5x/5 =190/5
x = 38
2x=76
3x-10= 3(38)-10=104

The measure of angles are 76 and 104
6 0
3 years ago
Last year, Keiko had $20,000 to invest. She invested some of it in an account that paid %7 simple interest per year, and she inv
erma4kov [3.2K]

Answer:

P_2 = \$6,000\\P_1 = \$14,000

Step-by-step explanation:

The formula of simple interest is:

I = P_0rt

Where I is the interest earned after t years

r is the interest rate

P_0 is the initial amount

We know that the investment was $20,000 in two accounts

_______________________________________________

<u><em>For the first account</em></u> r = 0.07 per year.

Then the formula is:

I_1 = P_1r_1t

Where

P_1 is the initial amount in account 1 at a rate r_1 during t = 1 year

I_1 = P_1(0.07)(1)\\\\I_1 = 0.07P_1

<u><em>For the second account </em></u>r = 0.05 per year.

Then the formula is:

I_2 = P_2r_2t

Where

P_2 is the initial amount in account 2 at a rate r_2 during t = 1 year

Then

I_2 = P_2(0.05)(1)\\\\I_2 = 0.05P_2

We know that the final profit was I $1,280.

So

I = I_1 + I_2=1,280

Substituting the values I_1, I_2 and I we have:

1,280 = 0.07P_1 + 0.05P_2

As the total amount that was invested was $20,000 then

P_0 = P_1 + P_2 = 20,000

Then we multiply the second equation by -0.07 and add it to the first equation:

0.07P_1 + 0.05P_2 = 1.280\\.\ \ \ \ \ \ \ \ +\\-0.07P_1 -0.07P_2 = -1400\\-------------

-0.02P_2 = -120\\\\P_2 = 6,000

Then P_1 = 14,000

4 0
3 years ago
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