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lara [203]
2 years ago
13

Ten men and ten women are to be put in a row. Find the number of possible rows if Beryl, Carol, and Darryl want to stand next to

each other in some order (such as Carol, Beryl, and Darryl, or Darryl, Beryl and Carol).
Mathematics
1 answer:
enyata [817]2 years ago
5 0

Answer: 6 possibilities.

Carol, Beryl, and Darryl

Carol, Darryl, and Beryl

Darryl, Carol, and Beryl

Darryl, Beryl, and Carol

Beryl, Darryl, and Carol

Beryl, Carol, and Darryl

Hope this helps :)

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Help!!!!!!!! Please
kvv77 [185]
The answer is C

Hope it helped
5 0
3 years ago
What is the length of XPY in terms of pi?
Elis [28]
Circumference of a circle = 2πr

Circumference of the whole circle= 2π(30) = 60π

360 - 90 = 270 

Length XPY = 270/360 x 60π = 45π

Answer: 45π m
5 0
3 years ago
Read 2 more answers
Now let’s practice what you have learned.<br><br><br> Solve the equation.<br> 4y – 4 = 28
laiz [17]

Answer:

<h2>y=8</h2>

Step-by-step explanation:

4y-4=28

4y=28+4

4y=32

y=32/4

y=8

now plug in 8 for y and check the equation true:

4y-4=28

4*(8)-4=28

32-4=28

28=28

So,  y is equal to eight 8

4 0
3 years ago
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Which pair of numbers has a GCF of 3? Group of answer choices (A) 3 and 18 (B) 8 and 24 (C)12 and 18 (D) 1 and 3
Arte-miy333 [17]

Answer:

A, B and C

Step-by-step explanation:

A) 3 and 18 = has 3 as factor

B) 8 and 24 = has 3 as factor

C) 12 and 18 = has 3 as factor

D) 1 and 3 = has as factor of 1 and 3

so the answer is A, B and C

5 0
3 years ago
Find the right quotient. 36m 5 n 5 ÷ (12m 3)
polet [3.4K]
ANSWER

The right quotient is

3  {m}^{2} {n}^{5}

EXPLANATION


The given expression is :

\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  \frac{36}{12}  \times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3\times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


Recall that,


\frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n}
We apply this property to obtain;



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3 \times   {m}^{5 - 3}  \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3  {m}^{2} {n}^{5}

5 0
3 years ago
Read 2 more answers
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