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Studentka2010 [4]
3 years ago
15

A rectangle has a perimeter of 18. The height of the rectangle is 4 cm. What is the area of the rectangle?

Mathematics
2 answers:
Lunna [17]3 years ago
6 0
20 cm, I think
The perimeter is 18 and the height is 4 cm.

4 cm x 2 = 8
We are multiplying it by two because there are two side in a rectangle that are the same height

18 - 8 = 10
We are finding the length of the rectangle
10\2 = 5
The length of the rectangle is 5

5 x 4 = 20
That is the area
Snezhnost [94]3 years ago
5 0

Answer:

20

Step-by-step explanation:

Perimeter of rectangle= 2l+2h so 2l+2(4)=18. SO 2l=10. l=5

Area=bh

(5)(4)=20cm

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What is the exact volume of the cone? with a 5 ft radius and a 16 ft height
andrew11 [14]

Answer:

The volume is 418.93 ft^3

Step-by-step explanation:

Here, we want to find the volume of a cone

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r = 5 ft

h = 16 ft

Substituting these values;

V = 1/3 * 3.142 * 5^2 * 16

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3 0
3 years ago
To make fruit punch for a party, we need 4 1⁄2 gallons of ginger ale, 1 gallon of strawberry juice, 2 3⁄4 gallons of frozen oran
lina2011 [118]

For this case we convert the mixed numbers to fractions:

4 \frac {1} {2} = \frac {2 * 4 + 1} {2} = \frac {9} {2}\\2 \frac {3} {4} = \frac {4 * 2 + 3} {4} = \frac {11} {4}

Now we add the fractions:

\frac{9} {2}+1+ \frac {11} {4} + \frac {1} {8} =

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\frac {36 + 8 + 22 + 1} {8} =\\\frac {67} {8} =

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4 0
3 years ago
Which graph best represents the relationship between time and the number of teams registered?
alexdok [17]
<h2>Explanation:</h2><h2></h2>

The complete question is in the attached file. So we have to choose between two graphs. On of them is a linear model while the other is an exponential model. From the statements, we have a relationship between time and the number of teams registered. So we can establishes variables in the following form:

x:\text{Time} \\ \\ y:\text{Number of teams registered}

We also know that each week 6 teams register to participate, so:

\bullet \ \text{For week 0:} \rightarrow \text{0 teams registered} \\ \\ \bullet \ \text{For week 1:} \rightarrow \text{6 teams registered} \\ \\ \bullet \ \text{For week 2:} \rightarrow \text{12 teams registered (Because 6+12)} \\ \\ \bullet \ \text{For week 3:} \rightarrow \text{18 teams registered (Because 12+6)}

As you can see, as x increases one week, y increases at a constant ratio of 6. Therefore, this can be modeled by a linear function given by the form:

y=6x

In conclusion, <em>the linear model (first graph below) is the one that bests represents  the relationship between time and the number of teams registered.</em>

7 0
3 years ago
!!!!!! URGENT PLS HELP ME ANSWER !!!!
laila [671]

Answer:

1) A = 547.1136, C = 82.896

2) A = 678.5226, C = 92.316

3) A = 844.5344, C = 102.992

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5) A = 1561.4906, C = 140.044

6) A = 994.8776, C = 111.784

Step-by-step explanation:

1)

A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{26.4}{2})^2 = 3.14 * 13.2^2 = 547.1136

C = \Pi D = 3.14 * 26.4 = 82.896

2)

A = \Pi r^2 = 3.14*(14.7)^2 = 678.5226

C = 2\Pi r = 14.7*2 * 3.14 = 92.316

3)

A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{32.8}{2})^2 = 3.14 * 16.4^2 = 844.5344

C = \Pi D = 3.14 * 32.8 = 102.992

4)

A = \Pi (\frac{D}{2})^2 =  3.14 * (\frac{44.5}{2})^2 = 3.14 * 22.25^2 = 1554.49625

C = \Pi D = 44.5*3.14 = 139.73

5)

A = \Pi r^2 = 3.14*22.3^2 = 1561.4906

C = 2\Pi r = 2 * 3.14 * 22.3 = 140.044

6)

A = \Pi r^2 = 3.14 * 17.8^2 = 994.8776

C = 2\Pi r = 2 * 3.14 * 17.8 = 111.784

8 0
3 years ago
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