Answer:
1/2 i think
Step-by-step explanation:
Answer:
69.01 m
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you ...
Tan = Opposite/Adjacent
The tangent function is useful for problems like this. Let the height of the spire be represented by h. The distance (d) across the plaza from the first surveyor satisfies the relation ...
tan(50°) = (h -1.65)/d
Rearranging to solve for d, we have ...
d = (h -1.65)/tan(50°)
The distance across the plaza from the second surveyor satisfies the relation ...
tan(30°) = (101.65 -h)/d
Rearranging this, we have ...
d = (101.65 -h)/tan(30°)
Equating these expressions for d, we can solve for h.
(h -1.65)/tan(50°) = (101.65 -h)/tan(30°)
h(1/tan(50°) +1/tan(30°)) = 101.65/tan(30°) +1.65/tan(50°)
We can divide by the coefficient of h and simplify to get ...
h = (101.65·tan(50°) +1.65·tan(30°))/(tan(30°) +tan(50°))
h ≈ 69.0148 ≈ 69.01 . . . . meters
The tip of the spire is 69.01 m above the plaza.
16 because the legth of TQ is the same as SR I hope thats right i checked with a ruler. :)
Answer:
a) Null hypothesis:
Alternative hypothesis:
b) 
c)
d)
e) For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12
Step-by-step explanation:
Information given
n=1000 represent the random sample selected
X=134 represent the number of young drivers ages 18 – 24 that had an accident
estimated proportion of young drivers ages 18 – 24 that had an accident
is the value that we want to verify
represent the significance level
Confidence=95% or 0.95
z would represent the statistic
Alternative hypothesis:
The statistic would be given by:
(1)
Part b
For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

Part c
For this case the statistic would be given by:
Part d
The p value can be calculated with the following probability:
Part e
For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12
Answer: 6.3093
<u>Step-by-step explanation:</u>



xln3 = 5ln4

x = 6.3093
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Answer: 5, 3,
, D
<u>Step-by-step explanation:</u>
a) x ≤ 0 so, f(-5) = | -5 | = 5
x ≤ 0 so, f(-3) = | -3 | = 3
x > 0 so, f(5) = 
b) graph D
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Answer: 
<u>Step-by-step explanation:</u>

= 
= 