What is the volume of a cylinder with a height of 15 and a radius of 11 ???????????????
1 answer:
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Answer:
BM: <u>y = (2/3) x + 16/3</u> with segment length of 2.77
Step-by-step explanation:
AC formula: m = (6-0)/(0-4) = -3/2
(y-0)/(x-4) = -3/2 y = (-3/2)x + 6 ... (1)
BM slope: BM⊥ AC m = 2/3
BM formula: (y-4) / (x- -2) = (y-4) / (x+2) = 2/3
y-4 = 2/3 x + 4/3
<u>y = (2/3) x + 16/3</u> ... (2) -2≤x≤0.31
intercept of AC and BM (M) from (1) and (2): (-3/2)x + 6 = (2/3) x + 16/3
(13/6) x = 2/3 x = (2/3) / (13/6) = 4/13 ≈ 0.31
y = (2/3) (4/13) + (16/3) = (8/39) + (208/39) = 216/39 = 72/13 ≈ 5.54
M (4/13 , 72/13) or (0.31 , 5.54)
segment BM = √(4/13 - -2)² + (72/13 - 4)² = √1300/169 = 2.77
Q6.
The slope-intercept form: y = mx + b
m - slope
b - y-intercept
We have: slope m = 3, y-intercept (0, 4) → b= 4
<h3>Answer: y = 3x + 4</h3>Q7.
2x + 4y = 4 |subtract 2x from both sides
4y = -2x + 4 |divide both sides by 4
y = -0.5x + 1
Only second graph has y-intercept = 1.
<h3>Answer: The second graph.</h3>Q8.
The point-slope form:
We have
Substitute:
Q9.
It's a vertical line. The equation of a vertical line is x = <em>a</em>, where <em>a</em> is any real number.
<h3>Answer: x = -4</h3>