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Paha777 [63]
3 years ago
14

Plsss help me im so stuck if i fail this test im screwed.

Mathematics
1 answer:
Leno4ka [110]3 years ago
6 0

Answer:

The Answer is 32

Step-by-step explanation:

14+9

other side is equal to 9

14+9+9

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Find the perimeter of the figure. If you need to use Pi in your computation, approximate its value as 3.14. Rectangle topped by
Rom4ik [11]

Answer:

74.6 m

Step-by-step explanation:

First look at the rectangle, which is 15 meters wide horizontally and 18 meters long vertically.  This rectangle contributes 2(18 m) + 15 m to the perimeter (the 15 m side is the bottom of the figure).  That comes to 2(18) m + 15 m, or 51 m.

Next, look at the semicircle.  Its diameter is 15 m and thus its total circumference is approximately (3.14)(15 m), or 47.1 m.  We take only half of this circumference in calculating the perimeter of this figure:  23.6 m.

The total perimeter of this figure is 23.6 m + 51 m, or approximately 74.6 m.

3 0
3 years ago
if I want a PlayStation for $300.00 and I get paid $10.50 a week how long would it take me to buy the PlayStation
konstantin123 [22]

Answer:

29 weeks or 4 months (not exactly)

Step-by-step explanation:

300/10.5 is 28.57

which 29 weeks, you earn 4 dollars and 50 cents left over

8 0
3 years ago
Find the median of this data: 18, 9, 17, 18, 15, 10, 18. If necessary, round to the nearest tenth.
Marta_Voda [28]
9, 10, 15, 17, 18, 18, 18

17

3 0
3 years ago
I just need this 2 questions need ASAP
tester [92]

Answer:

For the 1st question (4) For the 2nd question (1)

Step-by-step explanation:

(4) because 15000x+10000y needs to be less than or equal to 20000 or else they're going over the budget but x+y needs to be less than or equal to 15 as they can't make more than that.

(1) Divide both sides by pi and h then square root both sides.

7 0
3 years ago
Jina is chosing a 2-letter password from the letters A,B,C, and D. The password cannot have the same letter repeated in it. How
Fudgin [204]
The amount of passwords that Jina can make is only 12. Since the question says we are not allowed to use same letter twice that impacts the amount of passwords. In order to find the amount of passwords there is, we use the highest amount of letter choices, which is 4. Then the next letter can only have 3 letters. We can find out how many total passwords by doing 4*3 to get 12 different passwords.
8 0
4 years ago
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