We have the following dimensions:
w=wide
w+70=length
We have a right triangle:
leg₁=w
leg₂=w+70
hypotenuse=130
Pythagoras theorem:
leg₁²+leg₂²=hypotenuse²
Then:
w²+(w+70)²=130²
We have to solve that equation:
w²+(w+70)²=130²
w²+w²+140w+4900=16900
2w²+140w+4900-16900=0
2w²+140w-12000=0
(2w²+140w-12000)/2=0/2
w²+70w-6000=0
w=(-70⁺₋√(4900+24000)) / 2
=(-70⁺₋170) / 2
We have two possible solutions:
Solution 1
w=(-70-170)/2=-120 (this solution is not possible because the result is negative and it have no sense in this problem).
Solution 2
w=(-70+170)/2=50 (this is the right solution)
w=50
w+70=120
ANSWER: the length would be 120 u (u=units of length ) and the wide would be 50 u.
Answer:
The surface area is 116 square inches
Step-by-step explanation:
Given
-- Length
-- Width
-- Height
Required
Determine the surface area of the box [Missing from the question]
Since the box has no lid, the surface area is:
<em>Hence, the surface area is 116 square inches</em>
Answer:
4.9
Step-by-step explanation:
165.1-160.2
Answer:
Step-by-step explanation:
# of ways to succeed: 10*10*10*3*25*25--# of possible plates: 10*10*10*26*26*26----P(exactly one W) = [10^3*3*25^2]/[10^3*26^3] = 3*25^2/26^2 = 1875/17576
Answer:
area = 20x^2 - 10x - 30
Step-by-step explanation:
5(4x2 - 2x - 6)
area = 20x^2 - 10x - 30
