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saul85 [17]
3 years ago
15

Wich statement is true about a line and a point?

Mathematics
2 answers:
barxatty [35]3 years ago
6 0
<span>A point is a location and a line has many points located on it.</span>
Bogdan [553]3 years ago
3 0
A line are two rays in opposite directions and go on forever, and a point is a location on any type of line segment or shape ( see pictures for examples)

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Jillian and her friend went shopping. They were both looking for some new CD's. Jillian went to Music Matrix and spent $25.56 on
Vadim26 [7]

Answer:

Her friend got the better deal.

Step-by-step explanation:

For Jillians equation look at

$22.56/4 = $6.39 per CD

For her friends equation look at

$18.45/3 = $6.15 per CD

Jillian's friend got the better deal because she paid less per CD as shown in the equations above.

6 0
3 years ago
Consider this function: f(x) = -4x + 7. Which polynomial is equivalent to f(f(x))? A. 16x – 28 B. 16x2 – 56x + 49 C. 16x – 21 D.
Temka [501]

Answer:

The answer is :

C. 16x - 21

5 0
2 years ago
Using appropriate properties, find the value of 249² - 248²
Lady_Fox [76]

Answer:

\boxed{\bold{\huge{\boxed{497}}}}

Step-by-step explanation:

=> \sf 249^2 - 248^2

<u>Using Formula</u> \sf a^2 - b^2 = (a+b)(a-b)

<u><em>Where </em></u>

a = 249

b = 248

=> \sf (249+248)(249-248)

=> \sf (497)(1)

=> 497

3 0
3 years ago
What is the measure of angle Q to the nearest whole degree?<br> 43°<br> 49°<br> 53°<br> 58°
geniusboy [140]

Answer:

m∠Q ≈ 53°

Step-by-step explanation:

To find the measure of ∠Q, the law of cosines will need to be used. Lowercase letters represent the side lengths, while upper case letters represent angles.

In this situation, 'A' will be ∠Q. Therefore:

17² = 18² + 20² -2(18)(20)cosQ

Simplify:

289 = 324 + 400 -2(360)cosQ

Continue simplifying down:

-435 = -720cosQ

Divide both sides by '-720':

0.604 = cosQ

cos^{-1}Q = 0.604

m∠Q ≈ 52.83 or 53° rounded to the nearest whole degree.

3 0
3 years ago
Consider the following statement: The square of a prime number is not prime. (a) Write this as an if-then statement, using caref
Hitman42 [59]

The square of a prime number is not prime.

a) let x ∈ R, If x  ∈ {prime numbers}, then x^{2}∉{prime numbers}

there says that if x is a real and x is in the set of the prime numbers, then the square of x isn't in the set of prime numbers.

b) Prove or disprove the statement.

ok, if x is a prime number, then x only can be divided by himself. Now is easy to see that x^{2} = x*x can be divided by himself and x, then x*x is not a prime number, because can be divided by another number different than himself

7 0
3 years ago
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