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zepelin [54]
3 years ago
8

Dilate the point by a scale factor of 1/2 A(12,4)-->A'( , )

Mathematics
1 answer:
enyata [817]3 years ago
7 0

Answer:

No clue sorry

Step-by-step explanation:

I wish I could help but I cant

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which property is shown? 20×5×6=20×6×5 A commutative property B distibutivr C associative property or D none of these are correc
Contact [7]

A: communicative property, it is this because communicative property allows you to switch around the order.

5 0
3 years ago
Can someone think of a poem which starts with "Today I feel ...."<br>pls
GuDViN [60]
Yes, I shall give you an idea of how to start it. :)

Today I feel glad...
For all the friends I have had...
They gave me a pleasure...
For all that I treasure...
Special and dear to my heart. 

Ta da! :D Hope you like it
7 0
3 years ago
Read 2 more answers
In plane ABC the measure of angle A equals 42° the measure of angle B is five times the measure of angle C find the measure of a
krok68 [10]

Step-by-step explanation:

I think what is meant in the triangle ABC we have the three angles.

the sum of all angles in a triangle is airways 180 degrees.

so,

180 = A + B + C

180 = 42 + B + C

now, we know also that

B = 5×C

so, we can use that above

180 = 42 + 5×C + C

138 = 6×C

C = 138/6 = 23 degrees

B = 5×C = 5×23 = 115 degrees

7 0
2 years ago
a cube has sides of lengths a -3 which of the following expression best represents the volume of the cube
Semenov [28]

Answer: -27


Step-by-step explanation: the cube has a volume of -27 because -3 to the 3rd power (cubed) is -27

Hope this helps ☺


7 0
3 years ago
27.) Find the sum of the length of line segments EF and CD
Lelechka [254]

Answer:

5√10

Step-by-step explanation:

The distance between two points A(x_1,y_1) and B(x_2,y_2) on the coordinate plane is given by:

|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2 }

From the image attached the coordinates of the points are E(-1, -1), F(8, -4), C(-7, -4) and D(-1, 2).

Hence the lengths of the line segment EF and CD are:

|EF|=\sqrt{(8-(-1))^2+(-4-(-1))^2} =\sqrt{90}=3\sqrt{10} \\\\CD=\sqrt{(-1-(-7))^2+(-2-(-4))^2}=\sqrt{40}  =2\sqrt{10} \\\\Therefore:\\\\|EF|+|CD|=3\sqrt{10} +2\sqrt{10} =5\sqrt{10}

6 0
2 years ago
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