Answer:
f(x) = 2π (11 + sin x) √(1 + cos²x)
Step-by-step explanation:
Surface area of a curve rotated about y = a is:
S = ∫ 2π (y − a) ds,
where ds = √(1 + (dy/dx)²) dx.
y = 6 + sin x, and a = -5. dy/dx = cos x. Plugging in:
S = ∫₀²ᵖⁱ 2π (6 + sin x − -5) √(1 + cos²x) dx
S = ∫₀²ᵖⁱ 2π (11 + sin x) √(1 + cos²x) dx
Therefore, f(x) = 2π (11 + sin x) √(1 + cos²x).
Quartic => polynolial degree 4, i.e. the highest exponent of the variable is 4
trinomial=> three terms
leading coefficient = the coefficient in front of the term with the highest exponent.
standard form=> ax^4 + bx^3 + c^2 + dx + e
Solution:
2x^4 + x^3 + 0x^2 + 0x + 30
which is equal to 2x^4 + x^3 + 30: this is a quartic trinomial with leading coefficient 2, written in standard form.
Answer:
16<n+1
Step-by-step explanation:
Word by word... it ends with this equation..
8d-3 if youre asking for how that should be written. if not, i dont understand the question.
Answer:
1. 151.29 in.²
2. 413 km²
3. 75 cm²
Step-by-step explanation:
1. 12.3 in. × 12.3 in. = 151.29 in.²
2. 17.5 km × 23.6 km = 413 km²
<u>The third is a parallelogram. To find the area of a parallelogram you multiply the base and height.</u>
3. 15 cm × 5 cm = 75 cm²
For further calculation steps, look at these images:
These images are about multiplication and the decimal numbers in the problems have been converted to fractions.
